All categories

3 years ago

I. Direction: Write TRUE if the statement shows Principles of Facility Planning, and FALSE if

Computers and Technology

1 answer:

mr_godi [17]3 years ago

5 0

The following are either true or false in respect of Principles of Facility Planning/Management.

No. 1 is True. No. 2 is False. No. 3 is False. No. 4 is True. No. 5 is True.

<h3>What are the Principles of Facility Planning?</h3>

The main principles of facility planning are given below:

The planner must coordinate the plans with other government agencies that provide facilities
look at other options before selecting the final location for the facility
give adequate justification for the proposed facility
develop a management plan that includes design priorities and operational strategies
use the Life-Cycle Cost principles while designing
ensure that it is in line with the organisations plans/goals etc

Please see the link below for more about Facility Management:

brainly.com/question/5047968

You might be interested in

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

In order to prevent ports that are serving network hosts from being considered as best paths, what should be enabled to block bp

Sergio039 [100]

In order to prevent ports that are serving network hosts from being considered as best paths, BPDU guard should be enabled to block bpdus.

A bridge protocol data unit (BPDU) is known to be a kind of a data message that is known to be often transmitted in a local area network to be able to know or find loops in that given network topologies.

Hence, in the case above, In order to prevent ports that are serving network hosts from being considered as best paths, BPDU guard should be enabled to block bpdus.

See full question below

. In order to prevent ports that are serving network hosts from being considered as best paths, what should be enabled to block BPDUs?

a. BPDU filter

b. BPDU guard

c. root guard

d. BPDU drop

Learn more about ports from

brainly.com/question/10097616

#SPJ1

6 0

2 years ago

Hymter. Wants to workin The Energy career field with electrical energy

m_a_m_a [10]

Answer: what is the question

Explanation:

3 0

3 years ago

A more efficient design which involves the logical separation of a switch ports into different broadcast domains is known as a _

Nataly [62]

Answer: Virtual local-area network (VLAN)

Explanation:Virtual LAN(local area network) is the network that works on the particular geographical environment/domain in separative way by pretending to be working in the same local area.

This network works to maintain the security and network management in the geographical area .It is implement to gain the scalability and adaptability to the changes occurring in the network.

3 0

3 years ago

Which pdu is processed when a host computer is de-encapsulating a message at the transport layer of the tcp/ip model?.

yulyashka [42]

The PDU that is processed when a host computer is de-encapsulating a message at the transport layer of the tcp/ip model is segment.

<h3>What is this PDU about?</h3>

Note that in the transport layer, a host computer is said to often de-encapsulate what we call a segment so that they can be able to put back data to an acceptable or given format through the use of the application layer protocol that belongs to the TCP/IP model.

Therefore, The PDU that is processed when a host computer is de-encapsulating a message at the transport layer of the tcp/ip model is segment as it is the right thing to do.

Learn more about host computer from

brainly.com/question/553980

5 0

2 years ago