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adoni [48]
3 years ago
15

What is the smartest person ever

Computers and Technology
2 answers:
Murljashka [212]3 years ago
7 0

Answer: You!

Explanation: :D

blondinia [14]3 years ago
4 0
According to google, the smartest person ever is William James Sidis!



Born in Boston in 1898, William James Sidis made the headlines in the early 20th century as a child prodigy with an amazing intellect. His IQ was estimated to be 50 to 100 points higher than Albert Einstein's. He could read the New York Times before he was 2.
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Difference between sorting and filtering​
Serggg [28]
<h3>Sorting</h3>

The term “sorting” is used to refer to the process of arranging the data in <u>ascending or descending order</u>.

Example: Statistical data collected can be sorted alphabetically or numerically based on the value of the data.

<h3>Filtering</h3>

The process of data filtering involves selecting a <u>smaller part of your data set to view or analyze</u>. This is done by using that subset to view or analyze your data set as a whole.

Example: A complete set of data is kept, but only a portion of that set is used in the calculation, so the whole set is not used.

<em>Hope this helps :)</em>

5 0
1 year ago
Read 2 more answers
I have a question, but it's not a math question. Can anyone give me 5 unblockers for school computers? If you answer this, you w
ValentinkaMS [17]

Answer:

I mean if your talking about games then just try Cool math I will give link in comments

Explanation:

4 0
1 year ago
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For a new version of processor, suppose the capacitive load remains, how much more energy will the processor consume if we incre
erastovalidia [21]

Answer:

The answer is below

Explanation:

The amount of power dissipated by a processor is given by the formula:

P = fCV²

Where f = clock rate, C = capacitance and V = Voltage

For the old version of processor with a clock rate of f, capacitance C and voltage of V, the power dissipated is:

P(old) = fCV²

For the new version of processor with a clock rate of 20% increase = (100% + 20%)f = 1.2f, capacitance is the same = C and voltage of 20% increase = 1.2V, the power dissipated is:

P(new) = 1.2f × C × (1.2V)² = 1.2f × C × 1.44V² =1.728fCV² = 1.728 × Power dissipated by old processor

Hence, the new processor is 1.728 times (72.8% more) the power of the old processor

4 0
2 years ago
What is the Windows command to see the IP configuration of the PC?
lisov135 [29]
The answer is ipconfig
4 0
3 years ago
What will be the output of the following program? Assume the user responds with a 5.
FrozenT [24]

The output will be: You owe $ 15.0

4 0
3 years ago
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