Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
Answer:
−
4
x
+
20
Step-by-step explanation:
Answer:
Step-by-step explanation:
Applying logarithm rule
Log A - Log B= Log(A/B). Division rule
Now, Logx-log(x+13)=1
Log(x/(x+13))=1
Assume that the log is a natural log whose base is 10.
Then apply logarithm law
Log10 base 10=1
Comparing this to Log(x/(x+13))=1
This implies that
x/(x+13)=10
x=10(x+13)
x=10x+130
x-10x=130
-9x=130
x=130/-9
x=-14.444
In order to calculate how much wheat will be stored in each bag, let's divide the total amount of wheat by the number of bags:
Assuming that the amount of wheat each bag can hold is a whole number, so each bag can hold 96 kg (otherwise, each bag would hold 96.875 kg and there would be no wheat left).
Then, to find how much wheat will be left, let's calculate how much the 8 bags will hold, and then we subtract this value from the total:
So there will be 7 kg left.
This can be written as:
9-x>10
-x>1 (subtract 9 from both sides)
x<-1 (divide both sides by -1 and change the inequality sign)
Hope this helps
