Answer:
Step-by-step explanation:
The given function : 
[
]
[
]
Now , Differentiate both sides with respect to x , we will get
(By Chain rule)
[Note :
]

[
]

Hence, the derivative of the given function is
.
Answer:
7.
Solution given;
male=15
female=27
1st term=5*3
2nd term=3*3*3
now
Highest common factor=3
So
<u>The</u><u> </u><u>maximum</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>groups</u><u> </u><u>that</u><u> </u><u>the</u><u> </u><u>teacher</u><u> </u><u>can</u><u> </u><u>make</u><u> </u><u>is</u><u> </u><u>3</u><u>.</u>
<u>and</u><u> </u><u>each</u><u> </u><u>team</u><u> </u><u>contains</u><u> </u><u>5</u><u> </u><u>male and</u><u> </u><u>9</u><u> </u><u>female</u><u>.</u>
Answer:
the answer is 11
Step-by-step explanation:
dont know
Use distributive property in order to find the equivalent pieces of oi
(2^6)=1
take log on both sides,
xlog(2^6)=log(1)=0
=>
x=0, since log(2^6)>0
5^0=1
there is no value of x appearing in the equation, so x can be any valid number.