2 years ago

Find the slope between (7,-4)and (2,-4)

1 answer:

Pie2 years ago

3 0

$(\stackrel{x_1}{7}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-4}-\stackrel{y1}{(-4)}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{7}}}\implies \cfrac{-4+4}{5}\implies \cfrac{0}{5}\implies 0$

yes, is a vertical line, and all vertical lines have that slope.

You might be interested in

Shania has $45in her wallet. She spends $4 on snacks $8 on a movie ticket.What integer represents the change in amount of money

jeyben [28]

She has $32 left in her pocket

5 0

3 years ago

Please help me i dont know how to do the down part.

torisob [31]

Answer:

40, 60, 80, 100, 120, 140, 160, 180, 200

Step-by-step explanation:as the 12 goes up by 12 the 20 goes up by 20

8 0

2 years ago

Molly can read four-fifths of a page in the time it takes kayla to read one page. how many pages will kayla read in the time it

aev [14]

Kaila will read 1 page and 2 fifths

3 0

2 years ago

Anybody know the answers to this frl it’s due in 15 mins

hammer [34]

Answer:

4. j(11) = 8

I think it is linear

5. g(-3) = 18

No, it's a parabola since x is to the second power

6. f(-7) = 5

No, I think it's an absolute value function

7. h(0) = 13

I think it is linear, just the slope is 0

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If f'(x)=2/x and f(sqrt(e))=5, then f(e)=

docker41 [41]

$f'(x)=\dfrac2x$
$\implies f(x)=\displaystyle\frac2x\,\mathrm dx=2\ln|x|+C$

$f(\sqrt e)=5\implies 5=2\ln|\sqrt e|+C$
$\implies 5=\dfrac22\ln e+C$
$\implies C=4$
$\implies f(x)=2\ln|x|+4$
$\implies f(e)=2\ln|e|+4=6$

3 0

3 years ago