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Sladkaya [172]
2 years ago
15

Please help find the area of the figure above

Mathematics
2 answers:
kirza4 [7]2 years ago
6 0

Answer:

Area of the given figure is {\boxed{\sf{\green{84}}}} in²

Step-by-step explanation:

Firstly, finding the area of triangle by substituting the values in the formula

  • base = 6 in
  • height = 6 in

\begin{gathered} \qquad\longrightarrow{\sf{A_{(\triangle)} = \dfrac{1}{2} \times b \times h}}\\\\\qquad\longrightarrow{\sf{A_{(\triangle)} = \dfrac{1}{2} \times 6 \times 6}}\\\\  \qquad\longrightarrow{\sf{A_{(\triangle)} = \dfrac{1}{\cancel{2}} \times 6 \times \cancel{6}}}\\\\\qquad\longrightarrow{\sf{A_{(\triangle)} = 1 \times 6 \times 3}}\\\\\qquad\longrightarrow{\sf{A_{(\triangle)} = 6 \times 3}}\\\\\qquad\longrightarrow{\sf{A_{(\triangle)} = 18}}\\\\ \qquad{\star{\boxed{\sf{\purple{A_{(\triangle)} = 18 \: {in}^{2}}}}}}\end{gathered}

Hence, the area of triangle is 18 in².

\rule{200}2

Secondly, finding the area of rectangle by substituting the values in the formula :

  • length = 6 in
  • breadth = 11 in

\begin{gathered} \qquad{\twoheadrightarrow{\sf{A_{(Rectangle)} = l \times b}}}  \\  \\ \qquad{\twoheadrightarrow{\sf{A_{(Rectangle)} = 6 \times 11}}} \\  \\ \qquad{\twoheadrightarrow{\sf{A_{(Rectangle)} = 66}}} \\  \\ \qquad{\star{\boxed{\sf{\pink{A_{(Rectangle)} = 66 \:  {in}^{2}}}}}}\end{gathered}

Hence, the area of rectangle is 66 in².

\rule{200}2

Now, finding the total area of given polygon by substituting the values in the formula :

  • Area of triangle = 18 in²
  • Area of rectangle = 66 in²

\begin{gathered} \qquad{\rightarrow{\sf{Area = A_{( \triangle)} +  A_{(Rectangle)}}}} \\  \\ \qquad{\rightarrow{\sf{Area = 18 +  66}}} \\  \\ \qquad{\rightarrow{\sf{Area = 84}}} \\  \\ \qquad{\star{\boxed{\sf{\red{Area = 84\:  {in}^{2}}}}}}\end{gathered}

Hence, the area of given figure is 84 in².

\rule{300}{2.5}

Ksenya-84 [330]2 years ago
3 0

Answer:

Please mark my answer as Brainliest if you like it dear

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