All categories

3 years ago

Please Help !!!!!!!!!!!!!!

Mathematics

1 answer:

TEA [102]3 years ago

7 0

Answer:

Step-by-step explanation:

643-166=477

477÷18=26.5

Then, round to the nearest whole.

Which makes it 27 sets.

You might be interested in

Karen stacks a set of cans as shown. The top can has a diameter of 2 inches, the middle can has a diameter of 5 inches, and the

german

Answer:

Unknown

Step-by-step explanation:

What is the question? You have the information listed but you forgot to ask the question.

4 0

2 years ago

A set of data was published in the fall 2019 Phi Kappa Phi Forum regarding the performance of Major League Baseball (MLB) umpire

const2013 [10]

Answer:

The answer is "1.30".

Step-by-step explanation:

Proportion of population $=0.20$

Ratio sample $=\frac{70}{300}=\frac{7}{30}=0.23$

Statistics of the test:

$\to Z=\frac{(0.23-0.2)}{\sqrt{(\frac{0.2\times(1-0.2)}{300})}}\\\\$

$=1.30$

6 0

3 years ago

What is the answer?<br> 2500/x+20<br> =2500/(48.59)+20

sammy [17]

The answer would be 71.45

7 0

3 years ago

What is the slope-intercept form of the linear equation 2x–8y=322x–8y=32 ?

gladu [14]

2x - 8y = 32
-8y = -2x + 32
y = (-2/-8)x - 32/8
y = 1/4x - 4 <== slope intercept form

5 0

4 years ago

Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me

o-na [289]

Answer:

$\frac{3}{2}$

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

= - cos60cosx - sin60sinx

= - $\frac{1}{2}$ cosx - $\frac{\sqrt{3} }{2}$ sinx

squaring to obtain cos² (120 + x)

= $\frac{1}{4}$ cos²x + $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

= -cos60cosx + sin60sinx

= - $\frac{1}{2}$ cosx + $\frac{\sqrt{3} }{2}$ sinx

squaring to obtain cos²(120 - x)

= $\frac{1}{4}$ cos²x - $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + $\frac{1}{4}$ cos²x + $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x + $\frac{1}{4}$ cos²x - $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x

= cos²x + $\frac{1}{2}$ cos²x + $\frac{3}{2}$ sin²x

= $\frac{3}{2}$ cos²x + $\frac{3}{2}$ sin²x

= $\frac{3}{2}$ (cos²x + sin²x) = $\frac{3}{2}$

5 0

3 years ago