Suppose that the amount of algae in a pond doubles every 4 hours. If the pond initially contains 40 pounds of algae, how much al
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Answer:
`The answer is below
Step-by-step explanation:
P and q are points on the line y=2-4X. complete the coordinates of P and Q, P(0, ) Q( ,0)
Draw the line y= 2-4X for vales of x from -2 to 2
Solution:
The equation of a line is given by:
y = mx + b
Where y and x are variables, m is the slope of the line and b is the y intercept (that is value of y when x = 0).
The line of y = 2 - 4x is drawn by finding the corresponding values of y for x from -2 to 2 and plotting on a graph.
x: -2 -1 0 1 2
y: 10 6 2 -2 -6
The value P(0, ) Q( ,0)
The y coordinate of point P is gotten by substituting x = 0:
y = 2 - 4(0) = 2
P = (0, 2)
The x coordinate of point Q is gotten by substituting y = 0:
0 = 2 - 4x
4x = 2
x = 0.5
Q = (0.5, 0)
Let's call your speed "a"
her walking speed is then "2a"
and her friend's scooter speed is 10 a
let's also call the distance you need to walk "d"
so the time (t)you need is:
d/t=a
t=d/a
and her time is:
t=
(half a distance with the speed of 2a and half a distance (d/2) with the distance of 10 a
now we count (we know that her time is 30 minutes)
30=
//multiply by 20a
600a=
600a=6d/divide by 6
100a=d
Now, in order to calculate your time we need to calculate:
t=d/a
but we know how much is d now!
t=
=100
which means that you need 100 minutes, or 1 h 40 minutes!!!
her walking speed is then "2a"
and her friend's scooter speed is 10 a
let's also call the distance you need to walk "d"
so the time (t)you need is:
d/t=a
t=d/a
and her time is:
t=
(half a distance with the speed of 2a and half a distance (d/2) with the distance of 10 a
now we count (we know that her time is 30 minutes)
30=
600a=
600a=6d/divide by 6
100a=d
Now, in order to calculate your time we need to calculate:
t=d/a
but we know how much is d now!
t=
which means that you need 100 minutes, or 1 h 40 minutes!!!