f (x ) = 2 x + 5
For g (x) we will solve the system:
- 1 =-2 m + b
+
-9 = 2 m + b
----------------------
-10 = 2 b, b = -5
-9 = 2 m - 5
2 m = -4
m = -2
g ( x ) = - 2 x - 5
For h (X):
m = (-1-5 ) / ( 3-0 ) = -6/3 = -2
5 = 0 + b, b = 5
h ( x) = - 2 x + 5.
Now we have 4 linear functions:
1 ) f ( x ) = 2 x + 5
The slope is m = 2, y - intercept: y = 5 , zero: x = -2.5 and the function increases ( m > 0 ).
2 ) g(x) = - 2 x - 5
The slope is m = - 2, y-intercept: y =-5 , zero: x = -2.5 and the function decreases ( m < 0 ).
3 ) h ( x ) = - 2 x + 5
The slope is m = - 2, y - intercept . y = 5, zero: x = 2.5 and the function decreases.
4 ) j (x) = 2 x + 5
The slope is m = 2, y -intercept: y = 5, zero: x = -2.5 and the function decreases.
The functions f( x ) and j ( x ) are parallel and also g( x ) and h ( x ). They have the same slope.
The functions f ( x ) and j (x ) are increasing and h ( x ) and h ( x ) are decreasing.
Mult. $7.25 by 4 times 4 (4 PIZZAS per week, for 4 weeks):
$7.25(4)(4) = $116
Fine dining: 2($85) = $170
So, the fine dining costs more!
Answer:
The answer is obtuse scalene!
Step-by-step explanation:
The angle measurement is over 90 which classifies as obtuse and all the side measures are different so scalene is the second classification!
I hope this helps!
p.s. have any more questions? Post the question and comment the link below!
Ciao!
♥, Sadie
4x -3y=-3
-4x -4x
-3y=-4x-3
Then divide by -3
Answer
Y=4/3x+1
Answer:
The length of the shadow is decreasing 8 metres per second.
Step-by-step explanation:
In the attached figure, we draw the situation of the bear approaching the tree.
We can use the Tales to make some calculations.
The proportion between the height of the bear (h) and his shadow (S) is equal to the proportion between the height of the flashlight (H) and the sum of the distance of the bear (d) and the bear shadow.
This can be written as:

If we clear S we have:

We know that the distance is a function of time and it is reduced, as the bear approaches the tree, as a rate of 6 m/s.
We can express then the rate of variation of the shadow S as:

The length of the shadow is decreasing 8 metres per second.