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astraxan [27]
2 years ago
6

What does open and closed circles mean on a graph of a piecewise function? Pls help me out don’t get it

Mathematics
2 answers:
nexus9112 [7]2 years ago
8 0

Answer:

An open circle at the end of an interval means that the end point is not included in the interval, i.e. strictly less than or strictly greater than. A closed circle means the end point is included (equal to).

Open circles are used for numbers that are less than or greater than (< or >). Closed circles are used for numbers that are less than or equal to and greater than or equal to (≤ or ≥).

Step-by-step explanation:

oksano4ka [1.4K]2 years ago
8 0

Answer: An open circle at the end of an interval means that the end point is not included in the interval, i.e. strictly less than or strictly greater than. A closed circle means the end point is included (equal to).

Step-by-step explanation: Mark Me Brainliest.

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Rosey purchased 364 flowers to make centerpieces for a party. There are 13 tables. Each table will have 4 vases with the same nu
Olin [163]
7. honestly not 100% sure. i did 364 divided by 13 which was 28 so 28 flowers per table. and then 28 divided by 4. 7 flowers per vase.
8 0
2 years ago
Which points on the curve of x^2 - xy - y^2 = 5 have vertical tangent lines?
algol [13]

We need to differentiate this with respect to x to see if we can find an expression for the derivative of y at various points.  That will be the slope of the tangent to the curve.  Then we want to see where that derivative might be infinite -- i.e., where the tangent is vertical.

 

It's not written as a function, but it can still be differentiated using the chain rule:

 

x2 + xy + y2 = 3

(2x) + (x dy/dx + y dx/dx) + (2y dy/dx) = 0

 

(I used parentheses to show the differentiation of each term in the original equation.)

 

2x + x dy/dx + y + 2y dy/dx = 0

2x + y = -x dy/dx - 2y dy/dx

2x + y = dy/dx (-x -2y)

-(2x + y)/(x + 2y) = dy/dx

 

We have the derivative of y, but it's defined partly in terms of y itself.  That's OK.  Let's go on...

 

So where would the slope be infinite?  That would happen when x + 2y = 0, or y = -x/2

 

Let's plug that in for y in the original equation to find points where that's the case.

 

x2 + xy + y2 = 3

x2 + x(-x/2) + (-x/2)2 = 3

x2 - x2/2 + x2/4 = 3

3x2 / 4 = 3

x2 = 4

x = ±2

 

So we have two x values where the tangent might be vertical.  Let's plug them into the equation and see what the y values are.  First x = 2...

 

x2 + xy + y2 = 3

4 + 2y + y2 = 3

y2 + 2y + 1 = 0

(y + 1)2 = 0

y = -1

 

So at the point (2, -1) the tangent is vertical.

 

Now try x = -2...

 

x2 + xy + y2 = 3

4 - 2y + y2 = 3

y2 - 2y + 1 =0

(y - 1)2 = 0

y = 1

 

So at the point (-2, 1) the tangent is vertical.

8 0
2 years ago
Please help meee I need help
natta225 [31]

Answer:

5

6

Step-by-step explanation:

To solve, collect like terms

x ≥ 2 + 21/2

x ≥ 4 1/2

the whole number that would be greater than 41/2 would be 5

2.  2.7 + 3.3  > x

6 > x

8 0
3 years ago
What is the measure of the missing angle?
Westkost [7]
23.3 is the exact answer
5 0
2 years ago
Which term best describes the shape of this distribution?
borishaifa [10]

The shape of the distribution described the Left skewed.

<h3>What is left- skewed histogram?</h3>

A left skewed histogram is a histogram that attains a peak (which is the mode) towards the right side of the graph and has a “tail” towards the left side.

A histogram in which most of the data falls to the left of the graph's peak is known as a left-skewed histogram.

A left-skewed histogram is a type of histogram that is not symmetrical and in which the peak of the graph lies to the right of the middle value or the median.

Hence, considering the above definition the given histogram data falls on right side.

So, it is left skewed graph.

Learn more about left- skewed graph here:

brainly.com/question/1518646

#SPJ1

4 0
2 years ago
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