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weeeeeb [17]
3 years ago
7

BRAINLIST!!!!!!! PLEASE HELP!!!!!!!!

Mathematics
1 answer:
masya89 [10]3 years ago
7 0

2 \times  {3}^{1} =  {3}^{1} + 3 \: so \: x = 1
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Can someone help me out with this ??
nalin [4]

Answer:

1. b > -2

2. x <= 3

Step-by-step explanation:

Question 1:

-2(b + 5) < -6

Divide both sides by -2. Remember to change the inequality sign.

b + 5 > 3

Subtract 5 from both sides.

b > -2

Question 2:

-(x - 10) >= 7

Divide both sides by -1. Remember to change the inequality sign.

x - 10 <= -7

Add 10 to both sides.

x <= 3

6 0
4 years ago
Please help answer the following question
Elena L [17]

Answer:

D

Step-by-step explanation:

The unmarked angle of the triangle is also 40o. The triangle is marked with two equal sides (isosceles).

<2 + 40 + 40 = 180            Combine the left

<2 + 80 = 180                    Subtract 80 from both sides

<2 = 180 - 80

<2 = 100 degrees.

That's not the answer. We have to solve for x

<2 = x + 106

100 = x + 106       Subtract 106 from both sides

100 - 106 = x

x = - 6

8 0
3 years ago
Use Gauss-Jordan elimination to solve the following linear system.
marysya [2.9K]
Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]
mulstiply 2nd row by -1 and add to 3rd
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]
divde last row by 2
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 2rd row by 6 and add to top one
\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 1st row by -1 and add to 2nd
\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]
divide 2nd row by -3
\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]
mulstiply 2nd row by -1 and add to 1st row
\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]
divide 1st row by -3
\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]

rerange
\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer
7 0
3 years ago
How can you know if statement is true? <br> 1/2+3/8=4/10=2/5
mixas84 [53]

Answer:

Actually that's incorrect

Step-by-step explanation:

5 0
3 years ago
Can somebody plz help me Q 4-5-6<br> Plz and thank you
yarga [219]
I think it’s 7 hope this helps you
3 0
4 years ago
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