Answer:
The coefficient in the first term is 4
The constant is 6
There are 4 terms in this expression
The variable in the third term is y
Step-by-step explanation:
The constant is 6 because it is the only term without a variable, therefore the one term that will stay the same/remain constant.
The first term is 4x^2, the second term is -5x, the third term is 3y, and the fourth term is 6.
The variable in the first term is x^2, therefore the coefficient of x^2 is 4.
The center of the circle is (-3, 7)
The middle of the circle is on the line where x is -3, and on the line where y is 7
Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
