q + 12 - 2(q - 22) > 0 |use distributive property
q + 12 +(-2)(q) + (-2)(-22) > 0
q + 12 - 2q + 44 > 0 |combine like terms
(q - 2q) + (12 + 44) > 0
-q + 56 > 0 |subtract 56 from both sdies
-q > -56 |change the signs
<h3>q < 56</h3>
1/1+z+4/z+z^2 +1
1/2z =4/2z^2 +1
1/2z=2(z^2+2)/2z^2
1/2z=z^4+2z^2
z^5/2+2z^2
=therefore it has no solution I think this is the stes i m not sure sorry i m not sure ,try asking somebody else to cuz i m not sure
Answer: none of the above
Step-by-step explanation: when performing an hypothesis test and we want to make conclusion by comparing the p-value with the level of significance α
When p is greater than α, we reject the null hypothesis because it simply implies that we have a larger chance to commit a type 1 error ( α is the probability of committing a type 1 error an error where we reject the null hypothesis instead of accepting it ) which means we reject the null hypothesis.
When p is lesser than level of significance α, it means that we have a lesser chance of committing a type 1 error, which means we accept the null hypothesis.
Prob of selected students times prob of selecting boys times prob of selecting 3 boys
total students = 15b + 30g = 45 students
1. 10s/45t = 0.22
2. 15b/45t = 0.33
3. 3b/15b = 0.2
0.22×0.33×0.2=0.0148
1.48%
I'm not sure 100%... double check answer please
