Answer:
6,226 tiles of 9 in are needed to cover an area of 400 square feet
Step-by-step explanation:
Let
A -----> an area in square feet
t(A) ---> the total number of 9 in. tiles needed
we have

For A=400 ft^2
substitute in the equation and solve for t


That means -----> 6,226 tiles of 9 in are needed to cover an area of 400 square feet
Answer:
I think it's like 20.8....but I'm not sure
The value of x is 16/7
the value of y is 8/7
You mulitply 25 by .2 to get 5 and you add that to 25 to get $30