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3 years ago

Determine whether x=33 is a solution of the equation below 3= x/11

Mathematics

2 answers:

svp [43]3 years ago

6 0

Answer:

Yes, x = 33 is a solution

Step-by-step explanation:

To see if it is a solution, plug in 33 as x

3 = x/11

3 = 33/11

3 = 3

Since this is correct, x = 33 is a solution.

Lena [83]3 years ago

5 0

Given,

The value of x is 33.

$\implies \: 3 = \bf\dfrac{x}{11}$

$\implies \: 3 \times 11 = \bf x$

Putting the value of x ..

$\implies \: 33 = 33$

Left hand side is equal to right hand side, it means that x = 33 is a solution of given equation.

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zmey [24]

Answer:

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Step-by-step explanation:

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8 0

3 years ago

Use a 30degrees and -60degrees right triangle to find the exact value of the following trigonometric expression. Cot 30 degrees=

LuckyWell [14K]

The dirty little secret about trig is students mostly just need to understand the 45/45/90 right isosceles triangle and the 30/60/90 triangle, which is half an isosceles triangle.

I'm sure you have seen it many times already, so I'll remind you in the 30/60/90 right triangle the sides opposite those angles are respectively in the ratio $1: \sqrt{3}:2$ . Remember the smallest side is always opposite the smallest angle, etc. These make a right triangle because

$1^2 + \sqrt{3}^2 = 2^2$

So in this hypotenuse 2 triangle, the length 1 side is opposite the 30 degree angle and the $\sqrt{3}$ side is adjacent to it.

We could jump right to the answer but let's enumerate all the trig functions. Really you should memorize the sine and cosine so you can get these quickly.

$\cos 30^\circ = \dfrac{ \textrm{adjacent} }{ \textrm{hypotenuse} } = \dfrac{\sqrt{3}}{2}$

$\sin 30^\circ = \dfrac{ \textrm{opposite} }{ \textrm{hypotenuse} } = \dfrac{1}{2}$

$\tan 30^\circ = \dfrac{ \textrm{opposite} }{ \textrm{adjacent} }= \dfrac{1}{\sqrt{3}} =\dfrac{\sqrt{3}}{3}$

$\cot 30^\circ = \dfrac{ \textrm{adjacent} }{ \textrm{opposite}} = \dfrac{\sqrt{3}}{1} =\sqrt{3}$

$\sec 30^\circ = \dfrac{ \textrm{hypotenuse} }{ \textrm{adjacent}}= \dfrac{2}{\sqrt{3}}$

$\csc 30^\circ = \dfrac{ \textrm{hypotenuse} }{ \textrm{opposite}}= \dfrac{2}{1} = 2$

We want the cotangent, another way to get it is

$\cot 30^\circ = \dfrac{\cos 30^\circ}{\sin 30^\circ} = \dfrac{\sqrt{3}/2}{1/2} = \sqrt{3}$

8 0

3 years ago

Read 2 more answers

Jeremy makes 57,852 per year. Hiw much is his salary monthly? How much is it weekly?

dusya [7]

Monthly:

There are 12 months in a year. So, all we have to do is divide his yearly salary by 12.

57,852÷12

4,821

So, Jeremy's monthly salary is $4,821.

Weekly:

There are about 52 weeks in a year. So, we need to divide his yearly salary by 52.