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Galina-37 [17]
2 years ago
13

A. State whether the acceleration is positive, negative or zero for each section in the speed versus

Physics
1 answer:
bazaltina [42]2 years ago
5 0

Answer:

a=positive

b=0

c=positive

d=negative

Explanation:

a=acceleration depends on the speed and time. if the speed and time are increasing at the same rate, the acceleration value will be positive as the vehicle is speeding up.

b=the speed and time are not increasing, therefore the vehicle is either stationary or travelling at a steady pace.

c=same explanation as a

d=the speed and time are not increasing at the same rate as the speed is decreasing. this means that the car is slowing down

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What is the horsepower of a 1,500 kg car that can go to the top of a 360 m high hill in exactly 1 min?
Airida [17]

Answer:

W = m g h        work that must be done on car

P = W / t       power that must be input (in Watts)

P = m g h / t = 1500 kg * 9.8 m/s^2 * 360 m /  60 sec

P = 88,200 watts

P = 88,200 watts / 746 watts / hp = 118 hp

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2 years ago
Biological factor related to antisocial personality disorder is
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Schizotypal personality disorder and borderline personality disorder 
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Read 2 more answers
Help me please i dont understand
solniwko [45]

Answer:

It is b

Explanation:

The question tells you that the distance was increased 3 times the original distance, which means it was moved 3 times

5 0
3 years ago
Gas and oil from the dead creatures, the gas, and oil are trapped under layers of rock
scoundrel [369]

Answer:

Gas is on top of oil

Explanation:

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8 0
3 years ago
An electric dipole consisting of charges of magnitude 1.70 nC separated by 6.80 μm is in an electric field of strength 1160 N/C.
bazaltina [42]

Answer:

p = 1.16 10⁻¹⁴ C m     and  ΔU = 2.7 10 -11 J

Explanation:

The dipole moment of a dipole is the product of charges by distance

                        p = 2 a q

With 2a the distance between the charges and the magnitude of the charges

                        p = 1.7 10⁻⁹ 6.8 10⁻⁶

                        p = 1.16 10⁻¹⁴ C m

 

The potential energie dipole  is described by the expression

                       U = - p E cos θ

Where θ is the angle between the dipole and the electric field, the zero value of the potential energy is located for when the dipole is perpendicular to the electric field line

Orientation parallel to the field

                      θ = 0º

                      U = 1.16 10⁻¹⁴ 1160 cos 0

                      U1 = 1.35 10⁻¹¹ J

Antiparallel orientation

                       θ = 180º

                      cos 180 = -1

                      U2 = -1.35 10⁻¹¹ J

The difference in energy between these two configurations is the subtraction of the energies

                         ΔU = | U1 -U2 |

                         ΔU = 1.35 10-11 - (-1.35 10-11)

                         ΔU = 2.7 10 -11 J

6 0
3 years ago
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