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Flauer [41]
3 years ago
11

. A blowing ball with a 12 cm radius has an initial angular velocity of 5.0 rad/s. Sometime later, after rotating through 5.5 ra

dians, the bowling ball has an angular velocity of 1.5 rad/s. What is the average angular velocity of the bowling ball
Physics
1 answer:
Anna35 [415]3 years ago
7 0

Answer:

3.3 rad/sec.

Explanation:

The term '' average angular velocity'' can be defined as the rate at which the angular velocity changes. Kindly note that the rate in which the angular velocity changes is in radian per seconds[rad/sec]. So, without mincing words let's dive straight into the solution to the question above.

The radius of the blowing ball = 12cm, the initial angular velocity = 5.0 rad/s, the final angular velocity =  1.5 rad/s and the angle of rotation = 5.5 radians.

Therefore, from the definition of average angular velocity given above, the mathematical representation can be written as given below:

The average angular velocity  = [ the  initial angular velocity] + [the final angular velocity] / 2.

Thus, the average angular velocity = [ 5.0 rad/s + 1.5 rad/s] / 2 = 3.3 rad/s.

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Responder:

<h2>5.368N, </h2>

Explicación:

Según el principio pascal, establece que la presión aplicada en un punto sobre un líquido en un recipiente cerrado es igual a igual a la presión en cualquier otro punto del líquido.

Matemáticamente Presión ejercida por el pistón más pequeño = Presión ejercida por el pistón más grande.

La presión es la relación entre la fuerza y ​​su área de sección transversal.

P = Fuerza / Área de sección transversal

Sea P1 la presión sobre el pistón más pequeño y P2 la presión ejercida por el pistón más grande.

Como P1 = P2 entonces;

F1 / A1 = F2 / A2

Dado F1 = 450N, A1 = 14 cm², A2 = 167 cm² y F2 =?

Sustituyendo el valor conocido en la fórmula para obtener el requerido, tenemos;

\frac{450}{14} = \frac{F2}{167}\\  \\Cross\ multiplying\\\\14*F_2 = 450*167\\\\14F_2 = 75,150\\\\F_2 = \frac{75,150}{14} \\\\F_2 = 5,367.9N

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