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Flauer [41]
2 years ago
11

. A blowing ball with a 12 cm radius has an initial angular velocity of 5.0 rad/s. Sometime later, after rotating through 5.5 ra

dians, the bowling ball has an angular velocity of 1.5 rad/s. What is the average angular velocity of the bowling ball
Physics
1 answer:
Anna35 [415]2 years ago
7 0

Answer:

3.3 rad/sec.

Explanation:

The term '' average angular velocity'' can be defined as the rate at which the angular velocity changes. Kindly note that the rate in which the angular velocity changes is in radian per seconds[rad/sec]. So, without mincing words let's dive straight into the solution to the question above.

The radius of the blowing ball = 12cm, the initial angular velocity = 5.0 rad/s, the final angular velocity =  1.5 rad/s and the angle of rotation = 5.5 radians.

Therefore, from the definition of average angular velocity given above, the mathematical representation can be written as given below:

The average angular velocity  = [ the  initial angular velocity] + [the final angular velocity] / 2.

Thus, the average angular velocity = [ 5.0 rad/s + 1.5 rad/s] / 2 = 3.3 rad/s.

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3 years ago
A runner begins running at the beginning of 7th period and stops running at the end of the period. She runs at a pace of 10 km/h
MrRissso [65]

Answer:

She run for, t = 0.92 s

Explanation:

Given data,

The velocity of the runner, v = 10 km/h

The distance covered by the runner, d = 9.2 km

The relationship between the velocity, displacement and time is given by the formula,

                           t = d / v

Substituting the given values in the above equation,

                           t = 9.2 / 10

                             = 0.92 s

Hence, she ran for, t = 0.92 s

8 0
3 years ago
The repulsive force between two protons has a magnitude of 2.00 N. What is the distance between them?
Aloiza [94]

Answer:

The answer to your question is letter A.     r = 1.07 x 10⁻¹⁴ m

Explanation:

Data

F = 2 N

d = ?

q = 1.6 x 10 ⁻¹⁹ C

k = 8.987 Nm²/C²

Formula

                 F = K\frac{q1q2}{r^{2}}

Solve for r

                r = \sqrt{\frac{kq1q2}{F}}

Substitution

                r = \sqrt{\frac{8.987 x 10^{9}x1.6 x 10^{-19} x 1.6 x 10x^{-19}}{2}}

Simplification

                r = \sqrt{\frac{2.3 x 10^{-28}}{2}}

                r = \sqrt{1.15 x 10^{-24}}

Result

                r = 1.07 x 10⁻¹⁴ m

6 0
3 years ago
Read 2 more answers
The fastest pitched baseball was clocked at 46 m/s. assume that the pitcher exerted his force (assumed to be horizontal and cons
Zielflug [23.3K]
Using the Equation:
                                 v² = vi² + 2 · a · s    → Eq.1
where,
v = final velocity 
vi = initial velocity 
a = acceleration 
s = distance 

<span><span>We know that vi = 0 because the ball was at rest initially.
</span><span>
Therefore,

Solving Eq.1 for acceleration,
 
</span></span> v² = vi² + 2 · a · s
 v² = 0 + 2 · a · s
 v² = 2 · a · s
Rearranging for a,
a = v ²/2·<span>s
Substituting the values,
a = 46</span>²/2×1<span> 
a = 1058 m/s</span>² 

<span>Now applying Newton's 2nd law of motion,
 </span>
<span>F = ma
   = 0.145</span>×<span>1058

F = 153.4 N</span>
8 0
3 years ago
Einstein's theory of relativity is currently the best explanation of gravity. What is likely to happen to this theory in the fut
Trava [24]
I believe the answer is C
8 0
3 years ago
Read 2 more answers
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