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Flauer [41]
3 years ago
11

. A blowing ball with a 12 cm radius has an initial angular velocity of 5.0 rad/s. Sometime later, after rotating through 5.5 ra

dians, the bowling ball has an angular velocity of 1.5 rad/s. What is the average angular velocity of the bowling ball
Physics
1 answer:
Anna35 [415]3 years ago
7 0

Answer:

3.3 rad/sec.

Explanation:

The term '' average angular velocity'' can be defined as the rate at which the angular velocity changes. Kindly note that the rate in which the angular velocity changes is in radian per seconds[rad/sec]. So, without mincing words let's dive straight into the solution to the question above.

The radius of the blowing ball = 12cm, the initial angular velocity = 5.0 rad/s, the final angular velocity =  1.5 rad/s and the angle of rotation = 5.5 radians.

Therefore, from the definition of average angular velocity given above, the mathematical representation can be written as given below:

The average angular velocity  = [ the  initial angular velocity] + [the final angular velocity] / 2.

Thus, the average angular velocity = [ 5.0 rad/s + 1.5 rad/s] / 2 = 3.3 rad/s.

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3 years ago
A 2 kg rubber ball is thrown at a wall horizontally at 3 m/s, and bounces back the way it came at an equal speed. A 2 kg clay ba
Lyrx [107]

Answer:

THE RUBBER BALL

Explanation:

From the question we are told that

      The mass of the rubber ball is m_r   =  2 \ kg

      The  initial  speed of the rubber ball is  u =  3 \ m/s

      The final speed at which it bounces bank v  - 3 \ m/s

      The mass of the clay ball  is  m_c =  2  \ kg

       The  initial  speed of the clay  ball is u = 3 \ m/s

       The final speed of the clay ball is  v = 0 \  m/s

Generally Impulse is mathematically represented as

       I  =  \Delta p

where \Delta  p is the change in the linear momentum so  

       I  =  m(v-u)

For the rubber  is  

        I_r  =  2(-3 -3)

       I_r  = -12\ kg \cdot  m/s

=>     |I_r|  = 12\ kg \cdot  m/s

For the clay ball

       I_c  =  2(0-3)

        I_c =  -6 \ kg\cdot \ m/s

=>    | I_c| =  6 \ kg\cdot \ m/s

So from the above calculation the ball with the a higher magnitude of impulse is the rubber ball

       

8 0
4 years ago
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