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timofeeve [1]
4 years ago
5

30 POINTS!!! I need help ASAP, if someone comments just for points, or is incorrect just for points I will report! Please help!!

!
1.) A cue ball rolls with a speed of 1.8 m/s at an angle of 24 degrees relative to the edge of the billiards table. How large is the component of the velocity parallel to the edge of the table?
A) 0.73 m/s
B) 1.6 m/s
C) 1.8 m/s
D) 13 m/s
2.) A snowboarder travels 150m down a mountain slope that is 65 degrees above horizontal. What is his vertical displacement?
A) 32.5m
B) 58.9m
C) 63.4m
D) 135.9m
3.) A tennis player hits a ball at an angle of 50 degrees above horizontal so that it has an acceleration of 12 m/s². What is the horizontal component of the acceleration?
A) 7.7 m/s²
B) 9.2 m/s²
C) 10.4 m/s²
D) 48.9 m/s²
​

Physics
1 answer:
Anika [276]4 years ago
7 0

Answer:

1.) answer B

2.) answer D

3.) answer A

Explanation:

In all of these problems, it is essential to draw pictures in order to understand which trigonometric function to use according to the angle that the vector in question forms with the component requested. For all of them try to picture a right angle triangle with the vector as the hypotenuse, and the components as the triangle's shorter sides. Please refer to the three pictures attached as image for this answer a,d notice that the vector quantity known for all cases is represented in red, and the component to find is represented in green.

Problem 1) : the vector velocity makes an angle of 24 degrees with the edge of the table. So picture that vector as the hypotenuse of a right angle triangle for which you know the value: 1.8 m/s

So in this case, where you know the angle, the hypotenuse, and need to find the adjacent side to the angle, you use the cosine function as follows:

requested component =1.8 * cos (24) =1.644 \frac{m}{s}

which we round to 1.6 to match answer C).

For problem 2.) wee need to find the component opposite to the given angle in the triangle for which we also know the hypotenuse. So we use the sine function as follows:

requested component =150 * sin(65) = 135.94 m

which we round to 135.9 m to match answer D).

For problem 3.) we need to find the horizontal component to the acceleration which corresponds to the adjacent side to the known angle, so we use the cosine function as follows:

requested component =12 *cos(50) = 7.71 \frac{m}{s^2}

which we round tp 7.7 to match answer A).

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Ejercicio de la 2a ley de Newton
ICE Princess25 [194]

Answer:

Revisar las respuestas a cada problema, como se muestra mas adelante.

Explanation:

Para poder solucionar esta serie de problemas debemos de utilizar la segunda ley de Newton, la cual nos dice que la sumatoria de fuerzas sobre un cuerpo debe de ser igual producto de la masa por la aceleracion.

De esta manera tenemos:

ΣF = m*a

donde:

F = fuerza [N]

m = masa [kg]

a = aceleracion [m/s^2]

1 )

F = m*a

60 = m*4

m = 15[kg]

2)

F = m*a

a = 250/50

a = 5 [m/s^2]

3)

F = m*a

F = 80*2.5

F = 200 [N]

4)

F = m*a

800 = 1500*a

a = 0.533[m/s^2]

5)

F = m*a

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a = 100/500

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7 0
4 years ago
If a cup of water has holes in it than why does no water come out when when it is falling?
quester [9]

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It doesn't matter what the mass of a falling object is, and it  doesn't
matter whether a falling object is solid or liquid.  ALL falling objects
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ground at the same time.

If there was no air in the way, then a feather, a school bus, and a
battleship would accelerate at the same rate, fall together and hit
the ground at the same time.

When you drop a cup full of water that has holes in it, the cup and
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8 0
4 years ago
Read 2 more answers
A certain kind of glass has an index of refraction of 1.640 for blue light of wavelength 440 nm and an index of 1.595 for red li
DIA [1.3K]

Answer:

0.52°

Explanation:

refractive index for blue light, nb = 1.640

Refractive index for red light, nr = 1.595

Angle of incidence, i = 30°

Let the angle of refraction for blue light is rb and the angle of refraction for red light is rR.

By use of Snell's law for blue light

n_{b}=\frac{Sin i}{Sin r_{b}}

1.64=\frac{Sin 30}{Sin r_{b}}

1.64=\frac{0.5}{Sin r_{b}}

r_{b}=17.75^{\circ}

By use of Snell's law for red light

n_{R}=\frac{Sin i}{Sin r_{R}}

1.595=\frac{Sin 30}{Sin r_{R}

1.595=\frac{0.5}{Sin r_{R}}

r_{R}=18.27^{\circ}

The angle between the two beams, \theta =r_{R}-r_{b}

θ = 18.27° - 17.75°

θ = 0.52°

8 0
3 years ago
What other factor affected the gravitational force between the two objects in this simulation?
neonofarm [45]

Answer:

The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases

7 0
3 years ago
The wavelength​ (W) of a wave varies inversely as its frequency​ (F). A wave with a frequency of 600 kHz​ (kilohertz) has a leng
ratelena [41]

The wavelength of a wave varies inversely as its frequency, i.e.

W ∝ 1/F

A wave decreases its frequency from 600kHz to 300kHz, so let's calculate the scaling factor of W due to the change in F.

k = 1/(300/600) = 2

To find the new wavelength, multiply the original wavelength by k:

W = 2×129m

W = 258m

5 0
4 years ago
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