The kinetic energy for a large vehicle is different from that of a smaller vehicle, assuming that the vehicles are travelling at the same speed and stopping the same distance. This is because for a larger vehicle the kinetic energy is higher, as the mass for a larger vehicle, is more than the smaller vehicle.
Answer:
correct answer is (c) 15 J
Explanation:
given data
mass m1 = 2 kg
velocity V1 = 5 m/s
mass other = 3 kg
so mass m2 = 2+ 3 kg = 5 kg
solution
we will apply here conservation of momentum:
m1V1 = m2V2 ..........................1
put here value and we get velocity v2
(2.0) × (5.0) = (2.0 + 3.0) × V
solve it we get
10 = 5 × V
2
V2 = 2.0 m/s
so here kinetic energy will be
KE = ½ × m × v²
so
∆KE = ½ × m1 × (v1)² - ½ × m2 × (v2)
²
∆KE = 0.5 × 2 × 25 - 0.5 × 5 × 4
∆KE = 25 - 10
∆KE = 15 J
Answer:
a) a = 0
b) W = 29.72 N
Explanation:
a)The acceleration of an object is defined as the change of its speed with respect to a time interval, Because the briefcase remains at rest, its acceleration (a) is zero.
a=0
b) Calculation of the weight of the briefcase
The formula to calculate the weight is the following:
W= m*g Formula (1)
Where:
W : is the weight in Newtons (N)
m : is the mass in kilograms (kg)
g : is the acceleration due to gravity in meters over second square (m/s²)
Data
m=3.03 kg : mass of the briefcase
m=9.81 m/s² : acceleration due to gravity
We replace data in the formula (1)
W= m*g = 3.03 kg * 9.81 m/s²
W= 29.72 N
