3 years ago

Radio waves carry information from

Chemistry

1 answer:

arlik [135]3 years ago

5 0

Answer:

Answer is the C number . And plz mark me as brainlist.

Explanation:

AM to FM

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HELP!!! What has 5 valence electrons and is in period 3 on the periodic table?

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Answer:

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3 years ago

In 1928, 47.5 g of a new element was isolated from 660 kg of the ore molybdenite. the percent by mass of this element in the ore

vitfil [10]

To take the percent by mass of this element, we use the formula:

% mass = (mass of element / mass of ore) * 100%

% mass = (47.5 g / (660 kg * 1000 g / kg)) * 100*

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The number of neutrons in one atom of mercury with mass number 204 is:

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Number of neutrons is 121.

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Food and medical procedures can expose people to radiation. Therefore, the effects of radiation from a nuclear power plant are n

iogann1982 [59]

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two objects each have a mass of 5.0 g. one had a density of 2.7 g. and the other has a density of 8.4 g. which object has a larg

gulaghasi [49]

Answer:

The body with 2.7 $\frac{g}{(cm^3)}$ has a larger volume

Explanation:

There is a missespelling in the question. The units of density cannot be g, they usually are $\frac{g}{(cm^3)}$

In order to answer this question, we need to use the formula of the density of a body:

$Density = \frac{Mass}{Volume} = \frac{M}{V}$

For body A:

Mass (M) = 5.0 g

Density (D) = 2.7 $\frac{g}{(cm^3)}$

2.7 $\frac{g}{(cm^3)}$ = 5g * 1/V

V1 = 5g / (2.7 $\frac{g}{(cm^3)}$ )

V1 = 1.85 $1.85 cm^3$

For Body B:

Mass (M) = 5.0 g

Density (D) = 8.4 $\frac{g}{(cm^3)}$

8.4 $\frac{g}{(cm^3)}$ = 5g * 1/V

V2 = 5g / (8.4 $\frac{g}{(cm^3)}$ )

V2 = 0.59 $1.85 cm^3$

So V1 is bigger than V2

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4 years ago