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2 years ago

Help Pleaseeeeee im begging

Mathematics

2 answers:

Naddika [18.5K]2 years ago

6 0

Answer:

$f^{-1}(7)=2$

Step-by-step explanation:

$f^{-1}(7)$ means substitute x = 7 into the inverse function $f^{-1}$

$\implies f^{-1}(7)=\frac{7-1}{3} =2$

Andrew [12]2 years ago

5 0

Answer:

The answer should be C

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Artyom0805 [142]

Hey there :)

To find the slope with two points we will need to use the equation $\frac{y^2-y^1}{x^2-x^1}$

$x^1$ $x^2$ $y^1$ $y^2$

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Here is what the equation should look like when replaced with the numbers (it will be a fraction) :

$\frac{8 - (-20)}{5 - 3}$

We know that two negatives cancel out and make a positive, so the numerator would actually be 8 + 20.

Solve the fraction and we get $\frac{28}{2}$

28 divided by 2 is 14. The slope is 14.

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3 years ago

Which number line shows the solution to the inequality? y-2 <-5

spin [16.1K]

I think it would be A.

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3 years ago

Which of the following p-values will lead us to reject the null hypothesis if thelevel of significance equals 0.05?a.0.15b.0.10c

Ipatiy [6.2K]

Answer: 0.025

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3 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago

First-person to answer correctly with an explanation gets Brainliest

zzz [600]

Answer:

it has to be a or d

Step-by-step explanation:

they have 4000 in 1996 but we want 1991.so we get 15 percent of least time but i belive its d

7 0

3 years ago

Help Pleaseeeeee im begging​

Help Pleaseeeeee im begging