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3 years ago

Gary's pay is $15 per hour. He receives a 6% pay raise.

Mathematics

2 answers:

hjlf3 years ago

6 0

9514 1404 393

Answer:

see attached

Step-by-step explanation:

The calculation can be done by any method that adds 6% of the original salary to the original salary. That's equivalent to multiplying the original salary by 1.06 or 106%. The attachment shows some possibilities.

Fed [463]3 years ago

3 0

Answer:

_+_+_+_+_+_+_+_+_+_+_+_+_+_+_+_+_

Step-by-step explanation:

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Write the number 393,234,000,034 in words.

GarryVolchara [31]

Answer:

three hundred and ninety three billion, two hundred and thirty four million, and thirty four.

Step-by-step explanation:

billion is any digit that has seven to nine digits behind it

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4 years ago

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2 years ago

Find the area of the figure. (Sides meet at right angles.)

Harrizon [31]

Answer:

Step-by-step explanation:

to get the area of the given figure,

we need to split it in to two (see attached)

then area of a rectangle = length x width

A1 = 15 cm x 4 cm = 60 cm²

A2 = 5 cm x 4 cm = 20 cm²

Area = A1 + A2

= 60 + 20

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4 0

3 years ago

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$