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Ksju [112]
3 years ago
12

Which property of multiplication is shown? 9. (r:s) = (q.r).s

Mathematics
1 answer:
Lunna [17]3 years ago
3 0

Answer:

I think it is associative! Not sure though bc of the q!

Step-by-step explanation:

You might be interested in
Next sequence of 1,-2,-5,-8
melamori03 [73]

Answer:

-11,-14,-17

Step-by-step explanation:

Your numbers are decreasing by 3.

3 0
3 years ago
Jamie takes at random a counter from the bag and records the colour. Red : blue : green = 1:3:7 Jamie does this a number of time
Sonbull [250]

Answer: There are 249 times Jamie takes a counter from the bag.

Explanation:

Since we have given that

Ratio of colour of red to blue to green is 1:3:7.

Number of blue counters = 68

Let the total number of times Jamie does from the bag be x.

So, According to question,

\frac{3}{11}\times x=68\\\\x=\frac{11}{3}\times 68\\\\x=249.33\\\\=249\ approx.

Hence, there are 249 times Jamie takes a counter from the bag.

8 0
3 years ago
You are baking cookies for your class. There are 23 total students in your class and you have baked 12 cookies. Write and solve
KonstantinChe [14]
(x cookies) / (23 students - (12/2) students) = 2 cookies per student
[x / (23 - 6)] cookies per student = 2 cookies per student
23 students * (2 cookies per students) - 12 cookies = x cookies
The "students" unit cancels
46 cookies - 12 cookies = x cookies
x cookies = 34 cookies
3 0
3 years ago
Please help me to evaluate 6+7=8−15
zzz [600]
13=-7 which is not true
3 0
3 years ago
Read 2 more answers
If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
2 years ago
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