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3 years ago

What is the measure of angle UST?

Mathematics

1 answer:

aliina [53]3 years ago

6 0

I think the answer is c 30 degrees!!

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Find the equation of the line passing<br> through the points (2, 1) and (5, 10).<br> y = [? ]x + [ ]

sladkih [1.3K]

Answer:

$y=3x-5$

Step-by-step explanation:

$m=10-1/5-2$

$m=9/3$

$m=3$

$y=3x+b$

$x=2, y=1$

$1=3(2)+b$

$1=6+b$

$-5=b$

$y=3x-5$

8 0

3 years ago

Which logorithmic equation is equivalent to the exponential equation below? e^a=60

Alex73 [517]

Answer:

a = ln(60)

Step-by-step explanation:

4 0

3 years ago

R’(-1, 9) is the image of R after a reflection in the x-axis. What are the coordinates of R?

xz_007 [3.2K]

Answer:

Step-by-step explanation:

When we reflect over x-axis then the x-coordinate doesn't change and the y-coordinate changes its sign

in means if R = (x, y) then R' = (x, -y)

so we have:

x = -1 and -y = 9

y = -9

which gives R = (-1, -9)

6 0

3 years ago

Please help ASAP<br> Please I’ll mark you as brainlister

jenyasd209 [6]

Answer: 15.

Step-by-step explanation:

You divide the degrees by the side length. You get 15. So 15 is the answer.

4 0

3 years ago

Read 2 more answers

One thousand tonnes (1000 t, one t equals 10 cubed kg) of sand contains about a trillion (10 super 12) grains of sand. How many

Phantasy [73]

Answer with Step-by-step explanation:

Since 1 mole of sand will contain Avagadro's Number of sand particles (by definition of 1 mole)

Thus we have

1 mole of sand = $6.022\times 10^{23}$ sand particles

Thus in number of trillion sand particles we have no of trillion sand particles in 12 mole is

$\frac{6.022\times 10^{23}}{10^{12}}=6.022\times 10^{11}$

Now since it is given that mass of 1 trillion sand particles is 1000 tonnes Thus the mass of $6.022\times 10^{11}$ trillion sand particles is

$Mass=1000\times 6.022\times 10^{11}=6.022\times 10^{14}tonnes$

Part 2)

Since it is given that volume of 1 sand particle is $1.0mm^{3}$ thus the volume of 1 mole of sand is volume of $6.022\times 10^{23}$ sand particles

Thus volume of 1 mole is $V=1.00\times 10^{-18}km^{3}\times 6.022\times 10^{23}=6.022\times 10^{5}km^{3}$

Now since the Area of united states is $A=3.6\times 10^{6}mile^{2}=5.8\times 10^{6}km^{2}$

Thus the depth of the sand pile is

$Depth=\frac{Volume}{Area}=\frac{6.022\times 10^5}{5.8\times 10^6}=0.10387km=103.8meters$

4 0

3 years ago