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Kay [80]
2 years ago
10

What is -15xy + 25x factored

Mathematics
2 answers:
Oksanka [162]2 years ago
4 0

Since -5x is common to both factors, hence the factored form is;

-5x(3y - 5)

<h3>Factoring equation</h3>

Given the exprssion -15xy + 25x

Fing the factors of each term

-15xy = -5 * 3 * x * y

25x = 5 * 5 * x

Since -5x is common to both factors, hence the factored form is;

-5x(3y - 5)

Learn more on factored form here: brainly.com/question/43919

Oksanka [162]2 years ago
3 0

\Huge \tt \boxed{\boxed{ - 5x \times (3y-5)}}

\\\\

\Large \boxed{ \sf {Question  \: given↬\: -15xy + 25x \:  factored }}\\  \\  \Large \boxed{ \sf{ Lets  \: solve:- }}\\  \\\Large\boxed{\sf{⇒-15xy  +25x} }\\  \\  \Large \boxed{ \sf{⇒taking \:  -5x \: common \:  nd  \: rest \:  in \:  multiplaction}} \\  \\  \Large  \boxed{\sf{⇒-5x(3y-5)}} \\  \\  \\

\large\color{cyan}{\boxed{\frak{࿈\:Mr_Toxic}}}

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1. If two nonvertical lines are parallel, what do we know about their slopes? If two lines are perpendicular and neither is para
yanalaym [24]

Answer:

Two straight lines with slopes m and m' are parallel when m = m'

Two straight lines with slopes m and m' are perpendicular when m × m' = - 1.

Step-by-step explanation:

Let us assume that the two non-vertical lines in the slope-intercept form are

y = mx + c ........... (1) and  

y = m'x + c' ............ (2)

If those two lines are parallel then we can say the slope of them will be the same i.e. m = m'

Now, if given two straight lines (1) and (2) are perpendicular to each other and neither of them is parallel to the axes, then we can write m × m' = - 1. (Answer)

6 0
3 years ago
Is it C or no? Can u help please
Westkost [7]
 the answer is Probably C.

7 0
3 years ago
What is the average rate of change from x=0 to x=5
zmey [24]
80-40/5-0=40/5=8 through the slope formula
6 0
3 years ago
Read 2 more answers
Let a = x^2 + 4. Rewrite the following equation in terms of a and set it equal to zero. ( x^2 + 4 )^2 +32 = 12x^2 + 48
Aleks04 [339]
Answer:  In the resulting equation:  " a² - 12a + 32 = 0 " ;
________________________________________________________
  The "coefficient" of the "a" term is:  " - 12" . 
________________________________________________________
  The "constant" is:  " 32 " .
________________________________________________________

Explanation:

________________________________________________________

Let:   "a = x² + 4 " .

Given:  (x² + 4)²  + 32  =  12x² + 48  ; 
______________________________________________________

Factor:  "12x² + 48" into " (x² + 4) " ;

"12x² + 48"  =  12 (x² + 4) " ;
______________________________________________________

Given:    (x² + 4)²  + 32  =  12x² + 48 ; 

rewrite as;  "a² + 32 = 12a " ; 

Subtract "12a" from each side of the equation; 

"a² + 32 - 12a = 12a - 12a ;
 
to get:

" a² - 12a + 32 = 0 " .
___________________________________________________
The coefficient of the "a" term;  that is:

The "coefficient" of " -12a" ;  is:  "- 12" . 

The constant is:  "32<span>" .
</span>___________________________________________________
4 0
3 years ago
A flag pole has a rope that attaches to the ground from the top of the flagpole the rope create a 30° angle with the ground and
OLEGan [10]

Answer:

5.77\ \text{m}

11.54\ \text{m}

Step-by-step explanation:

p = Height of pole

h = Length of role

b = Distance between the bottom of the rope and bottom of the pole = 10 m

\theta = Angle between the rope and the ground = 30^{\circ}

\tan\theta=\dfrac{p}{b}\\\Rightarrow p=b\tan\theta\\\Rightarrow p=10\tan30^{\circ}\\\Rightarrow p=5.77\ \text{m}

The length of the rope is 5.77\ \text{m}

\cos\theta=\dfrac{b}{h}\\\Rightarrow h=\dfrac{b}{\cos\theta}\\\Rightarrow h=\dfrac{10}{\cos30^{\circ}}\\\Rightarrow h=11.54\ \text{m}

The length of the pole is 11.54\ \text{m}

3 0
3 years ago
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