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V125BC [204]
3 years ago
15

Use the diagram to derive the law of cosines.

Mathematics
1 answer:
vladimir1956 [14]3 years ago
7 0

Answer:

B) x= a cos C

Step-by-step explanation:

You might be interested in
Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =
swat32

Answer:

Test statistic, t_{s} = -0.603 (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

\bar{d} = \frac{\sum x-y}{n}

\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625

Standard deviation: SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1}  }

\sum d^{2}  = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2}  = 63

SD = \sqrt{\frac{63 - 8 *  (-0.625)^2}{8-1}  }

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n}  } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8}  }

t_{s} = -0.6033

6 0
3 years ago
The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.0 minutes and
strojnjashka [21]

Answer:

P ( 5 < X < 10 ) = 1

Step-by-step explanation:

Given:-

- Sample size n = 49

- The sample mean u = 8.0 mins

- The sample standard deviation s = 1.3 mins

Find:-

Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.

Solution:-

- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:

                                   X ~ N ( u , s /√n )

Where

                            s /√n = 1.3 / √49 = 0.2143

- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:

                        P ( 5 < X < 10 ) = P (    (5 - 8) / 0.2143 <  Z  <  (10-8) / 0.2143   )

                                                 = P ( -14.93 < Z < 8.4 )

- Using standard Z-table we have:

                        P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1        

7 0
3 years ago
Leila and jo are two of the partners in a business. Leila makes $3 in profits for every $4 that jo makes. If jo makes $60 profit
Aleonysh [2.5K]

Let

x-------> Leila 's profit

y------> Jo's profit

we know that

\frac{x}{y} =\frac{3}{4} ----------> equation 1

For y=\$60

<u>Find the value of x</u>

Substitute the value of y in the equation 1

\frac{x}{60} =\frac{3}{4}

x=60*\frac{3}{4}

x=\$45

therefore

<u>the answer is</u>

Leila make \$45 in profit

5 0
3 years ago
Read 2 more answers
Help please - first question
Afina-wow [57]
The answer should be x=60. ABD are an equilateral triangle all the angles must add up to 180. 60*3=180. Also if you have a protractor you can measure the angle C, the 60 degrees part and measure it against A, D and B. Hope this helps.
5 0
3 years ago
For the standard form of two billion three Hundred fifty thousand four Danielle wrote 2,350,400,000 what error did she make what
Leona [35]
I believe the correct answer is 2,300,500,004
7 0
3 years ago
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