Answer:- a.The given expression is equivalent to 
Given expression:- ![[\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%283xy%5E%7B-5%7D%29%5E3%7D%7B%28x%5E%7B-2%7Dy%5E2%29%5E%7B-4%7D%7D%5D%5E%7B-2%7D)
![=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B%283%29%5E3x%5E3y%5E%7B-5%5Ctimes3%7D%7D%7Bx%5E%7B-2%5Ctimes-4%7Dy%5E%7B2%5Ctimes-4%7D%7D%5D%5E%7B-2%7D.........%28a%5Em%29%5En%3Da%5E%7Bmn%7D)
![=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B27x%5E3y%5E%7B-15%7D%7D%7Bx%5E8y%5E%7B-8%7D%7D%5D%5E%7B-2%7D)
![=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}](https://tex.z-dn.net/?f=%3D%5B27x%5E%7B3-8%7Dy%5E%7B-15-%28-8%29%7D%5D%5E%7B-2%7D............%5Cfrac%7Ba%5Em%7D%7Ba%5En%7D%3Da%5E%7Bm-n%7D)
![=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}](https://tex.z-dn.net/?f=%3D%5B27x%5E%7B-5%7Dy%5E%7B-7%7D%5D%5E%7B-2%7D%3D%2827%29%5E%7B-2%7D%28x%5E%7B-5%7D%29%5E%7B-2%7D%28y%5E%7B-7%7D%29%5E%7B-2%7D.........%28a%5Em%29%5En%3Da%5E%7Bmn%7D)
Thus a. is the right answer.
Answer: Yes
Step-by-step explanation: All vertical lines have the same slope and because of that they are always parallel.
Answer:
(3+5ab^2)*2ab^2
Explanation: To find the perimeter of a rectangle, add the lengths of the rectangle's four sides. If you have only the width and the height, then you can easily find all four sides (two sides are each equal to the height and the other two sides
7n +13p + -5 = 15 Hope I helped
<span>The slope of the line passing through the points (0, 3) and (5, 7) is 4/5</span>
