The bisector of angle APQ passes through O and this is illustrated below.
<h3>How to illustrate the information?</h3>
From the information given, the center is O. and the circle passes through O and cuts at K.
In this case, it should be noted that the circles are equal according to the SAS test.
Here, AOB + APQ = 180° (Linear pair)
2AOB = 180
AOB = 90.
Therefore, the bisector of angle APQ passes through O.
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The answer is If you would like to find the expression that is equivalent to (t*s)(x), you can calculate this using the following steps:
s(x) = x - 7
t(x) = 4x^2 - x + 3
(t*s)(x) = t(s(x)) = t(x - 7) = <span>4(x - 7)^2 - (x - 7) + 3 = 4(x - 7)^2 - x + 7 + 3
The correct result would be </span>4(x – 7)2 – (x – 7) + 3.
For this case we have a function of the form:

Where,
A: initial amount
b: decrease rate
x: time in days
Substituting values we have:

Therefore, the graph of the function is a decreasing exponential function in the first quadrant and that has an initial value of 40.
Answer:
graph of exponential function going from left to right in quadrant 1 through the point 0, 40 and approaching the x axis
If 42% of paint is white to get the result we just have to finid 42% of 18.
42% of 18 = 0.42*18=7.56$ - its our result