Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
Answer:
y^5+11y^3-2y^3-22
Step-by-step explanation:
The least common multiple is : 18
It is the lowest amount that can be reached.
Step-by-step explanation:
Solving
2x + 6 = 4x - 4
Bringing like terms on one side
6 + 4 = 4x - 2x
10 = 2x
10 / 2 = x
5 = x
Find a common denominator which is 12
1*3=3 4*3=12 so 3 3/12
then 5*2=10 6*2=12 so 2 10/12
2 10/12+3 3/12= 5 13/12
13/12= 1 1/12 plus 5= 6 1/12
so your answer would be 6 1/12
