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Komok [63]
2 years ago
10

Add: (112 + 2) + (92 - 4)

Mathematics
2 answers:
pantera1 [17]2 years ago
5 0

Answer:

See below.

Step-by-step explanation:

(112+2)+(92-4)

114+88

202

-hope it helps

icang [17]2 years ago
5 0
202 I guess I used a calculator
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If y equals -18 when x is 6 find x when y is 6
Mekhanik [1.2K]

Answer:

x=-2

Step-by-step explanation:

-6/18=x/6

simplify the -6/18 into -1/3,

-1/3=x/6

cross product,

3*x=-1*6

3x=-6

x=-6/3

x=-2

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3 years ago
Does anyone know the answer to this ?
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What if you divide it by 100?
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1 year ago
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Mike is a car salesman. He earns $200 for every car he sells plus a 3% commission. If mike sells 3 cars in one week for a total
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1570.29 Is what I came up with, though I'm not entirely certain. I just figured I'd give it a shot

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3 years ago
CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is
Rufina [12.5K]

Answer:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

y=\sin(x)\cos(x)

Take the derivative of both sides with respect to x:

\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]

We need to use the product rule:

(uv)'=u'v+uv'

So, differentiate:

y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]

Evaluate:

y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))

Simplify:

y'=\cos^2(x)-\sin^2(x)

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

0=\cos^2(x)-\sin^2(x)

Now, let's solve for x. First, we can use the difference of two squares to obtain:

0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))

Zero Product Property:

0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)

Solve for each case.

Case 1:

0=\cos(x)-\sin(x)

Add sin(x) to both sides:

\cos(x)=\sin(x)

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

0=\cos(x)+\sin(x)

Subtract sine from both sides:

\cos(x)=-\sin(x)

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

And we're done!

Edit: Small Mistake :)

5 0
3 years ago
What’s the answer ?
elena-14-01-66 [18.8K]

Answer:

It is 9x^3.

Step-by-step explanation:

36x^4 and 45x^3.

GCF of 36 and 45 = 9

GCF of x^4 and x^3 = x^3

GCF of 36x^4 and 45x^2 = 9x^3.

7 0
3 years ago
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