Find the 14th term of the arithmetic sequence - 4x - 1, - 9x - 6 , -14x-11
1 answer:
Answer:
-69x-66
Step-by-step explanation:
1) given: a₁=-4x-1; a₂=-9x-6; a₃=-14x-11. Find: a₁₄-?
2) a₁₄=a₁+13d, where d - the difference between neighbor-terms;
3) d=a₂-a₁; ⇔ d= -9x-6+4x+1= -5x-5;
4) a₁₄= -4x-1+13*(-5x-5)= -69x-66.
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