Question

Find the 14th term of the arithmetic sequence - 4x - 1, - 9x - 6 , -14x-11

Answer 1

Answer:

-69x-66

Step-by-step explanation:

1) given: a₁=-4x-1; a₂=-9x-6; a₃=-14x-11. Find: a₁₄-?

2) a₁₄=a₁+13d, where d - the difference between neighbor-terms;

3) d=a₂-a₁; ⇔ d= -9x-6+4x+1= -5x-5;

4) a₁₄= -4x-1+13*(-5x-5)= -69x-66.