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allochka39001 [22]
2 years ago
13

Find the 14th term of the arithmetic sequence - 4x - 1, - 9x - 6 , -14x-11

Mathematics
1 answer:
Yanka [14]2 years ago
3 0

Answer:

-69x-66

Step-by-step explanation:

1) given: a₁=-4x-1; a₂=-9x-6; a₃=-14x-11. Find: a₁₄-?

2) a₁₄=a₁+13d, where d - the difference between neighbor-terms;

3) d=a₂-a₁; ⇔ d= -9x-6+4x+1= -5x-5;

4) a₁₄= -4x-1+13*(-5x-5)= -69x-66.

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What is the area of this composite figure? <br> A . 12ft²<br> B. 80ft²<br> C. 88ft²<br> D. 100ft²
Eva8 [605]

Answer:

c.)88^2

Step-by-step explanation

4 0
2 years ago
A school debate team has four girls and six boys. A total of four of the team members will be chosen to participate in the distr
alex41 [277]
Procedure:

1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)

Solution

1) the number of teams of four members that can be formed are:

10*9*8*7 / (4*3*2*1) = 210

2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls

Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6

Number of different teams with 2 boys and 2 girls = 15 * 6 = 90

3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:

90/210 = 3/7
 
7 0
3 years ago
I get
dybincka [34]

Answer:

Absolute minimum = 1.414

Absolute maximum = 2.828

Step-by-step explanation:

g(x,y)=\sqrt {x^2+y^2} \ constraints: 1\leq x\leq 2 ,\ 1\leq y\leq2

For absolute minimum we take the minimum values of x and y.

x_{minimum} =1\\y_{minimum}=1\\

Plugging in the minimum values in the function.

g(1,1)=\sqrt {1^2+1^2}\\g(1,1) = \sqrt{1+1}\\g(1,1)=\sqrt {2}\\g(1,1)=\pm 1.414\\

Absolute minimum value will be always positive.

∴ Absolute minimum = 1.414

For absolute maximum we take the maximum values of x and y.

x_{maximum} =2\\y_{maximum}=2\\

Plugging in the maximum values in the function.

g(2,2)=\sqrt {2^2+2^2}\\g(2,2) = \sqrt{4+4}\\g(2,2)=\sqrt {8}\\g(2,2)=\pm 2.828\\

Absolute maximum value will be always positive.

∴ Absolute maximum = 2.828

3 0
3 years ago
On $500 at 6% for 18 months what is the interest
blsea [12.9K]
It would be $45. The equation is 500×0. 06×1.5
6 0
3 years ago
T/2 + 3 = 5 (solve for t)
Mashutka [201]

Answer:

t = 4

Step-by-step explanation:

Given

\frac{t}{2} + 3 = 5 ( subtract 3 from both sides )

\frac{t}{2} = 2

Multiply both sides by 2 to clear the fraction

t = 2 × 2 = 4

7 0
3 years ago
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