Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
Answer:
Absolute minimum = 1.414
Absolute maximum = 2.828
Step-by-step explanation:
For absolute minimum we take the minimum values of 
and 
.
Plugging in the minimum values in the function.
Absolute minimum value will be always positive.
∴ Absolute minimum = 1.414
For absolute maximum we take the maximum values of and .
Plugging in the maximum values in the function.
Absolute maximum value will be always positive.
∴ Absolute maximum = 2.828
It would be $45. The equation is 500×0. 06×1.5
Answer:
t = 4
Step-by-step explanation:
Given
+ 3 = 5 ( subtract 3 from both sides )
= 2
Multiply both sides by 2 to clear the fraction
t = 2 × 2 = 4
