<h2>
Answer with explanation:</h2>
As per given , we have
Sample size : n= 5
Degree pf freedom = : df= 5-1=4
Significance level for 90% confidence = 
Using t-value table , t-critical value for 90% confidence:
Margin of error of 
: 
Interpretation : The repair cost will be within $12.39 of the real population mean value 90% of the time.
Answer:
the correct answer is C 8/15
Step-by-step explanation:
We can set up a proportion.
32/128 = x/100
32 * 100 = 3200
128 * x = 128x.
Now we have 128x = 3200.
All we need to do is divide 3200 by 128, so 3200 / 128 = 25, so your answer is 25%.
A = P(1 + rt)
Where:
<span>·
</span>A = Total Accrued Amount (principal + interest)
<span>·
</span>P = Principal Amount
<span>·
</span>I = Interest Amount
<span>·
</span>r = Rate of Interest per year in decimal; r = R/100
<span>·
</span>R = Rate of Interest per year as a percent; R = r * 100
<span>·
</span>t = Time Period involved in months or years
A = 15,000(1+ 0.07(5))
A = 20,250 they acquired in total for 5 years
The yearly amount the get is 15,000 xx 0.07 = $ 1050 per
year
So in the next 25 years addition of 1050x25 = $26250 they
will get
