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3 years ago

A square is dilated by a scale factor of 3/5

Mathematics

1 answer:

Lerok [7]3 years ago

5 0

Answer:

1 and 1/5

Step-by-step explanation:

if you add the numerator and leave the denominator you'll get that its basically just 6/5

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PLEASEE HELP I ONLY HAVE 3 MINUTES LEFT PLEASE HELP ME

skelet666 [1.2K]

Answer:The graph of F is shifted 3 to the left and 1 up

Step-by-step explanation:

On the x axis, negative is left, positive is right. On the y axis, negative goes down, positive goes up. X is negative, it goes to the left, and y is positive, it moves up. Hope this helps and good luck!

6 0

3 years ago

If,<br><img src="https://tex.z-dn.net/?f=%5Cbf%7B%7B%20x%3Ay%20%3D%2013%3A8%20%5C%3A%20%20%5C%3A%20%20and%20%5C%3A%20%20%5C%3A%2

SpyIntel [72]

Find LCM for the second term or common terms from both ratio that is 8 and 6

The LCM is 24

x:y = 13×3:8×3

y:z= 6×4:9×4

x:y= 39:24

y:z= 24:36

So, x:y:z= 39:24:36

Hope This Helps You ❤️

8 0

3 years ago

A random sample of 401 student were recent survey regarding their class standing freshmen software junior senior and their major

SOVA2 [1]

the Solution

$Pr(\text{STEM)}=\frac{158}{401}=0.394$ $Pr(\text{Sophomore)}=\frac{87}{401}=0.217$ $Pr(sophomore|Non-stem)=\frac{68}{401}=0.170$ $Pr(\text{sophomore and Non-stem)=}\frac{87}{401}\times\frac{243}{401}=\frac{21141}{160801}=0.1315$

To ascertain whether Sophomore and Non-stem are dependent, we have to test the following:

$\begin{gathered} If\text{ Pr(sophomore or Non-stem) = Pr(sophomore and Non-stem),} \\ \text{then we conclude that both events are Independent,} \\ \text{otherwise, they are dependent.} \end{gathered}$ $\begin{gathered} Pr(\text{sophomore or Non-stem)=Pr(sophomore)+Pr(Non-stem)} \\ -Pr(\text{sophomore and Non-stem)} \end{gathered}$ $Pr(\text{Sophomore or Non-stem)=}\frac{87}{401}+\frac{243}{401}-(\frac{87}{401}\times\frac{234}{401})$ $=\frac{330}{401}-\frac{21141}{160801}=0.82294-0.13147=0.69147$

Cleary, we have that sophomore and non-stem events are dependent events since 0.69147 is not the same as 0.13147.

4 0

1 year ago

What is the answer? Really confused on how to figure this out

Natasha2012 [34]

Answer:

$C.\frac{2(x+2)}{(x-3)}$

Step-by-step explanation:

$\frac{x^2+5x+6}{x-6} \div \frac{x^2-9}{2x-12} \\\\Now,\\Before\ touching\ the\ expression,\ lets\ look\ at\ the\ indiviual\ terms\ and\ try\ to factorize\ them.\\x^2+5x+6\\=(x^2+3x+2x+6)\\=x(x+3)+2(x+3)\\=(x+2)(x+3)\\\\x-6=(x-6)\\\\x^2-9\\=(x)^2-(3)^2\\=(x-3)(x+3)\\\\2x-12\\=2(x-6)\\\\Hence,\\\frac{x^2+5x+6}{x-6} \div \frac{x^2-9}{2x-12}\\=\frac{(x+3)(x+2)}{x-6} \div \frac{(x-3)(x+3)}{2(x-6)}\\By\ flipping\ the\ second\ term\ to\ its\ reciprocal, we\ get:\\$ $\frac{(x+3)(x+2)}{x-6} * \frac{2(x-6)}{(x-3)(x+3)}\\\\=(x+2)*\frac{2}{(x-3)} \\=\frac{2(x+2)}{(x-3)}$

6 0

3 years ago

Read 2 more answers

Hey besties! Can you solve this question i will make you brainlist

Vesna [10]

Answer:

Step-by-step explanation:

Let x be the total no. of strawberries, Let Sue be "S", Let Jim be "J" and Dan be "D"

S = 2x/7

J = 54+S -> J = 54+(2x/7)

D = 78

J+D = 5x/7

54+(2x/7)+78 = 5x/7

132+2x/7 = 5x/7

132 = (5x/7)-(2x/7)

132 = 3x/7

132*7 = 3x

924/3 = x

x = 308.

Therefore, there were initially 308 strawberries in the basket.

Of which; Sue had two-sevenths: 88, Jim had 142 and Dan had 78

To verify our answer, add these to see if we get 308

S+J+D = 308

88 + 142 + 78 = 308

8 0

2 years ago