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garik1379 [7]
3 years ago
14

. The larger number is 19 more than the smaller number. What are the numbers?

Mathematics
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer:

1

Step-by-step explanation:

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Which of the following statements uses the commutative property of addition?
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This package of sliced cheese costs $2.97. How much would a package with 18 slices cost at the same price per slice?
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Brent created a mural, 4/5 of which he painted in shades of blue. Three eighths of the blue area is sky blue. What portion of th
Snezhnost [94]

Answer: \frac{3}{10} of the mural is sky blue.


Step-by-step explanation:

Let x be the full portion of mural.

Since, \frac{4}{5} of mural is painted in shades of blue.

Therefore, the blue portion=\frac{4}{5}x

Also, Three eighths of the blue area is sky blue.

Therefore, the portion of the mural is sky blue=\frac{3}{8}\times\frac{4}{5}x

The portion of the mural is sky blue=\frac{12}{40}x

Simplify, by dividing numerator and denominator by 4, we get

The portion of the mural is sky blue=\frac{3}{10}x


5 0
2 years ago
Help me please please
Mariana [72]

Answer:

scale factor P to Q: 4/5   scale factor Q to P: 5/4

Step-by-step explanation:

Divide original length over new length and you'll get the scale factor.

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2 years ago
Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
3 years ago
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