The balanced chemical equation would be as follows:
<span>AlCl3(aq) + 3AgC2H3O2(aq) -> 3AgCl(s) + Al(C2H3O2)3(aq)
</span>
We are given the concentrations of the reactants. We use these values to calculate for the volume of aluminum chloride needed. We do as follows:
0.500 mol/L AgC2H3O2 (0.020 L) ( 1 mol AlCl3 / 3 mol AgC2H3O2 ) ( 1 L / 0.250 AlCl3 ) = 0.0133 L or 13.3 mL of AlCl3 solution is needed
Decantation is a process for the separation of mixtures of immiscible liquids or of a liquid and a solid mixture such as a suspension.
Answer:
See explanation
Explanation:
In this case, we have to know where we have to do. We have to remove a "Br" and put a methyl group and for this, we need to use a Gilman reaction. (See figure 1). We have to start with <u>bromomethane</u> that reacts with Li to form <u>methyllithium</u>. Then we have to do the reaction with Copper to obtain the Gilman reagent <u>dimethylcopper</u>. Finally, we have to do the reaction with the halide <u>1-bromocyclohexene</u> to form <u>1-methylcyclohexene</u>.
See figure 1
I hope it helps!
Answer:
Exactly 18.228749999999973 grams :)
I recommend rounding to 1 d.p
The amount of atoms of Phosphorus in 3.80 mol of copper (II) phosphate would be equivalent with :
3.80 mol x (6.022 x 10^23 molecules)/ (1 mol)
Hope this helps