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Troyanec [42]
3 years ago
15

5. Which is an example of inertia?

Chemistry
1 answer:
Hitman42 [59]3 years ago
6 0

Answer:

Explanation:

D. When the truck driver slammed on the brakes, all the boxes in the back

of the truck slid forward.

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An atom has 8 protons, 8 neutrons and 9 electrons. is thus a cation, anion, or neutral atom?​
Black_prince [1.1K]

Answer:

It is an <u>Anion</u> because there are more electrons than protons making it negative

7 0
3 years ago
What is the volume of the sample at stp ?
Natasha2012 [34]
At stp the volume is 22.4 L .

<span>hope this helps!</span>
3 0
3 years ago
What volume of 0.305 m agno3 is required to react exactly with 155.0 ml of 0.274 m na2so4 solution? hint: you will want to write
LuckyWell [14K]

The balanced chemical equation for reaction of AgNO_{3} and Na_{2}SO_{4} is as follows:

2 AgNO_{3}+Na_{2}SO_{4}\rightarrow 2NaNO_{3}+Ag_{2}SO_{4}

From the balanced chemical equation, 2 mol of AgNO_{3} reacts with 1 mol of  NaNO_{3}.

First calculating number of moles of NaNO_{3} as follows:

M=\frac{n}{V}

On rearranging,

n=M\times V

Here, M is molarity and V is volume. The molarity of NaNO_{3}  is given 0.274 M or mol/L and volume 155 mL, putting the values,

n=0.274 mol/L\times 155\times 10^{-3}mL=0.04247 mol

Since, 1 mol of NaNO_{3}  reacts with 2 mol of  AgNO_{3} thus, number of moles of  AgNO_{3}  will be 2\times 0.04247 mol=0.08494 mol.

Now, molarity of  AgNO_{3} is given 0.305 M or mol/L thus, volume can be calculated as follows:

V=\frac{n}{M}=\frac{0.08494 mol}{0.305 mol/L}=0.2785 L=278.5 mL

Therefore, volume of  AgNO_{3} is 278.5 mL.

4 0
3 years ago
During a reaction in an aqueous solution, the concentration of bactants
STALIN [3.7K]

Answer:

my define it will be turst me is c

5 0
3 years ago
Consider a transition of the electron in the hydrogen atom from n=3 to n=7.
kow [346]

<u>Answer:</u>

<u>For a:</u> The wavelength of light is 1.005\times 10^{-6}m

<u>For b:</u> The light is getting absorbed

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the wavelength of light, we use Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 1.097\times 10^7m^{-1}

n_f = Higher energy level = 7

n_i= Lower energy level = 3

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{3^2}-\frac{1}{7^2} \right )\\\\\lambda =1.005\times 10^{-6}m

Hence, the wavelength of light is 1.005\times 10^{-6}m

  • <u>For b:</u>

There are two ways in which electrons can transition between energy levels:

  1. <u>Absorption spectra:</u> This type of spectra is seen when an electron jumps from lower energy level to higher energy level. In this process, energy is absorbed.
  2. <u>Emission spectra:</u> This type of spectra is seen when an electron jumps from higher energy level to lower energy level. In this process, energy is released in the form of photons.

As, the electron jumps from lower energy level to higher energy level. The wavelength is getting absorbed.

6 0
3 years ago
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