Let the number of reserved tickets = x
Let the number of lawn seats = y
Constraint functions:
Maximum capacity means 
For concert to be held 
means 
Objective functions :
Maximum profit equation p = 65x +40y
Intersection points :
(10000,10000) (20000,0)(2500,2500)(5000,0)
p at (10000,10000) = 65(10000) + 40(10000) = $1050000
p at (20000,0) = 65(20000) + 40(0) = $1300000
p at (2500,2500) = 65(2500) + 40(2500) = $262500
p at (5000,0) = 65(5000) + 40(0) = $325000
Hence maximum profit occurs when all 20000 reserved seats are sold and the profit is $1300000
Please find attached the graph of it.
Answer:

44000(1+.0825)^10=$97214.65≈$97215 to the nearest dollar
When you add the decimals it’s the same as regular adding. You line up the decimals and then add all the way across and when you get to the decimal carry it down
Answer:
r≈12.89
Step-by-step explanation:
Using the formula
C=2πr
Solving for r
r=C
2π=81
2·π≈12.89155
Answer:
1. equal
2. add to 180
3. equal
4. add to 180
Step-by-step explanation:
as 1 and 3 are linear pairs
2 and 4 are vertically opposite angles