Answer:
49 cars
Step-by-step explanation:
Probability of cars to be sold in a week,a = 0.2
Probabiity of cars not sold in a week, b = 0.8
Number of cars estimated to be sold in a week = 20 and 60 cars in 3 weeks
Using, P(x) = nCx *(a)∧x * (b)∧n - x, where n = 3 weeks, x = 1 week
P(x=1) = 3C1 * (0.2) * (0.8)² = 3 X 0.2 X 0.64 X 60 cars = 23 cars
P(x=2) = 3C2 * (0.2)² * (0.8) = 3 X 0.04 X 0.8 X 60 cars = 6 cars
Number of cars three weeks from now: 20 + 23 + 6 = 49 cars
G(x) = G(1/2)
So just plug in
20(1/2) - 189
10-189
= -179
Your final answer is -179
Hope this helped! Let me know if you have any questions.
Mark me Brianliest please:)
Answer:
5 4/9
Step-by-step explanation:
I did it myself
<span>-(x + 5) = 5
-x - 5 = 5
-x = 5 + 5
-x = 10
x = -10</span>