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2 years ago

The slopes of perpendicular lines are

Mathematics

1 answer:

romanna [79]2 years ago

7 0

Answer:

A. Negative reciprocals

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Answer:

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2 years ago

A cable for a power transformer forms

posledela

Answer:

32 ft

Step-by-step explanation:

From the diagram, the side opposite the 60° angle is 28 feet.

We are looking for the approximate length of the cable.

The approximate length of the cable is the hypotenuse of the triangle shown.

Recall the sine ratio from SOH-CAH-TOA

Which means Sine of the angle is Opposite/Hypotenuse

Let the hypotenuse be h, then we have:

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3 years ago

2. Today Carly’s bank account contains $82. Yesterday she made a withdrawal of $25. What was the bank account balance before Car

Slav-nsk [51]

Is it together or different questions to the reading

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3 years ago

58.15<br> If f(x) = 5x + 40, what is f(x) when x = -5?

Ket [755]

Answer:

Step-by-step explanation:

if you put x=-15

f(x) = 5*-5 +40

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=15

7 0

2 years ago

Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin

sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

$\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}$

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x$

7 0

2 years ago