Answer:
91.6 km/h
Step-by-step explanation:
Let v = average speed of van = 65 km/h and v' = average speed of car. Let t be the time the car starts to move. The van started 35 minutes earlier at t' = (t + 35/60) h.
Since distance d = vt where v = velocity and t = time, the distance moved by the van d = vt' = v(t + 35/60) and that moved by the car is d' = v't.
Since the car catches up with the van after it had moved a distance of 130 km, d = d' = 130 km.
So d = v(t + 0.583)
Substituting d = 130 km and v = 65 km/h, we have
130 km = 65 km/h(t + 0.583)
130 km = (65t + 37.895 )km
subtracting 37.895 from both sides, we have
130 km - 37.895 km = 65t
92.105 = 65t
dividing both sides by 65, we have
t = 92.105/65
= 1.417 h
≅ 1.42 h
Since d = d' = v't,
v' = d'/t
= 130 km/1.42 h
= 91.55 km/h
≅ 91.6 km/h
So, the average speed of the car is 91.6 km/h
Answer:
I think it's -15 I'm not 100% sure
No, Bec it can not be divided by itself? Anyway no also Bec it’s a decimal
Slope of a line = Y2-Y1/X2-X1
--> (-4)-(-6)/6-4
= -4+6/ 6-4
= 2/2
The slope of the line = 1
Answer:
New avaerage if 2 students (15 year old) left = 13
Step-by-step explanation:
Given:
Average age of 20 students = 13.2
Find:
New avaerage if 2 students (15 year old) left
Computtaion:
Sum of all 20 student's age = 20 x 13.2
Sum of all 20 student's age = 264
Sum of current 18 student's age = 264 - 15 - 15
Sum of current 18 student's age = 234
New avaerage if 2 students (15 year old) left = 234 / 18
New avaerage if 2 students (15 year old) left = 13
