All categories

3 years ago

What is y + 11 = 1/3(x + 3) in standard form?

1 answer:

3 0

Standard form is y=Mx+b so first step is to isolate y:
Y=1/3(x+3)-11

Then use order of operations to simplify the x to a whole number. First multiply by three:
3y=x+3-33

Now combine like terms:
3y=x-30

Finally,
Divide to make y have a coefficient if one:

Y= 1/3x -10

You might be interested in

What is the seventh multiple of 4 answer for brainiest

qwelly [4]

Answer:

the answer is prolly 28

3 0

2 years ago

Read 2 more answers

The hypotenuese of an isosceles right triangle is 13 inches. The midpoints of its sides are connected to form an inscribed trian

Georgia [21]

Answer:

The Sum of the areas of theses triangles is 169/3.

Step-by-step explanation:

Consider the provided information.

The hypotenuse of an isosceles right triangle is 13 inches.

Therefore,

$x^2+x^2=169\\2x^2=169\\x=\frac{13}{\sqrt{2} }$

Then the area of isosceles right triangle will be: $A=\frac{1}{2} x^2$

Therefore the area is: $A=\frac{169}{4}$

It is given that sum of the area of these triangles if this process is continued infinitely.

We can find the sum of the area using infinite geometric series formula.

$S=\frac{a}{1-r}$

Substitute $a=\frac{169}{4} \ and\ r=\frac{1}{4}$ in above formula.

$S=\frac{\frac{169}{4}}{1-\frac{1}{4}}$

$S=\frac{\frac{169}{4}}{\frac{3}{4}}$

$S=\frac{169}{3}$

Hence, the Sum of the areas of theses triangles is 169/3.

7 0

3 years ago

What is the value of x to the nearest tenth?

pav-90 [236]

It would be 5.4 knowing that 9.6 is not the diameter you would need a larger radius so that when it is doubled you get a good number :)

5 0

3 years ago

In the diagram, bisects FGI.

valentina_108 [34]

Answer:

C 100%

Step-by-step explanation:

3 0

2 years ago

A photograph has a width of 9.5cm and an area of 104.5cm(squared). An enlargement is to be made that has a width of 19cm. What w

SashulF [63]

Answer: Area = 389.5cm^2

Explanation:

Area = 104.5cm^2
Width = 9.5cm

Find Length:

L = A/W
L = 104.5/9.5
L = 11cm

Find the enlargement:

let x be the enlargement:
9.5cm + x = 19cm
x = 19 - 9.5
x = 9.5cm

Thus, the enlargement is 9.5cm.

L (after enlarging) = 11 + 9.5 = 20.5cm

W (after enlarging) = 19cm

Find area after enlarging:

A = 20.5 x 19
A = 389.5cm^2

5 0

3 years ago