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Ghella [55]
3 years ago
13

What is y + 11 = 1/3(x + 3) in standard form?

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
3 0
Standard form is y=Mx+b so first step is to isolate y:
Y=1/3(x+3)-11

Then use order of operations to simplify the x to a whole number. First multiply by three:
3y=x+3-33

Now combine like terms:
3y=x-30

Finally,
Divide to make y have a coefficient if one:

Y= 1/3x -10
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1. f(6) if f(x) = 4x I know the answer I just need the explanation please thank you!
suter [353]
So when you have one of these, it’s just asking you so solve it as if x were 6 (as you see where the x in f(x) is replaced with a 6.

so you’d sub x for 6

giving you:

4 x (6)

which = 24

hope that makes sense :)
6 0
2 years ago
Read 2 more answers
What is the volume of the sphere that has a diameter of 3? use 3.14 for pie​
aev [14]

Hey ! there

Answer:

  • <u>1</u><u>1</u><u>3</u><u>.</u><u>0</u><u>4</u><u> </u><u>unit </u><u>cube</u>

Step-by-step explanation:

In this question we are provided with a sphere <u>having</u><u> </u><u>radius </u><u>3 </u><u>units </u>and <u>value </u><u>of </u><u>π </u><u>is </u><u>3.</u><u>1</u><u>4</u><u> </u><u>.</u><u> </u>And we're asked to find the<u> </u><u>volume</u><u> of</u><u> </u><u>sphere</u><u> </u><u>.</u>

For finding volume of sphere , we need to know its formula . So ,

\qquad \qquad \: \underline{\boxed{ \frak{Volume_{(Sphere)} =  \dfrac{4}{3} \pi r {}^{3} }}}

<u>Where</u><u> </u><u>,</u>

  • π refers to <u>3.</u><u>1</u><u>4</u>

  • r refers to <u>radius</u><u> of</u><u> sphere</u>

<u>Sol</u><u>u</u><u>tion </u><u>:</u><u> </u><u>-</u>

Now , we are substituting value of π and radius in the formula ,

\quad \longrightarrow \qquad \: \dfrac{4}{3}   \times 3.14 \times (3) {}^{3}

Simplifying it ,

\quad \longrightarrow \qquad \: \dfrac{4}{3}  \times 3.14 \times 3 \times 3 \times 3

Cancelling 3 with 3 :

\quad \longrightarrow \qquad \: \dfrac{4}{ \cancel{3}}  \times 3.14 \times 3 \times 3 \times  \cancel{3}

We get ,

\quad \longrightarrow \qquad \:4 \times 3.14 \times 9

Multiplying 4 and 3.14 :

\quad \longrightarrow \qquad \:12.56 \times 9

Multiplying 12.56 and 9 :

\quad \longrightarrow \qquad \:    \pink{\underline{\boxed{\frak{113.04  \: unit \: cube}}}} \quad \bigstar

  • <u>Henceforth</u><u> </u><u>,</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>sphere</u><u> </u><u>having </u><u>radius </u><u>3 </u><u>units </u><u>is </u><em><u>1</u></em><em><u>1</u></em><em><u>3</u></em><em><u> </u></em><em><u>.</u></em><em><u>0</u></em><em><u>4</u></em><em><u> </u></em><em><u>units </u></em><em><u>cube </u></em><em><u>.</u></em>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>

5 0
1 year ago
Worth 50 points!!! The equation A = r(<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7BC%7D%7B2%7D%20" id="TexFormula1" title=" \f
jasenka [17]
Times both sides by 2
2A=rC
divide both sides by r
C= \frac{2A}{r}
4 0
3 years ago
The equation 4(x – 3)2 – 5 = 139 has two solutions: one positive and one negative. What is the
AlekseyPX

Answer:

Step-by-step explanation:

4(x-3)2-5 = 139

(4x-12)-5=139

-20x + 60 = 139

-20x +60 - (60) = 139- 60

-20x = 79 divide both sides by -20

x = -3.95

3 0
3 years ago
Please help with question 4A,B please<br> Thank you
mrs_skeptik [129]
<h3>Given</h3>
  • C(t) = 40 cm + t·(2/5 cm/s) . . . circumference of a circle vs time
<h3>Find</h3>
  • dr/dt for radius r
  • r at t=4 seconds
<h3>Solution</h3>

The circumference and radius of a circle are related by

... C = 2πr

so the radius in terms of circumference is

... r = C/(2π)

... r(t) = (40 +0.4t)/(2π) = (1/π)(20 cm + 0.2t cm/s)

Then dr/dt is

... dr/dt = 0.2/π cm/s

And the radius at t=4 s is

... r(4) = (1/π)(20 + 0.2·4) cm

... r(4) = 20.8/π cm

4 0
2 years ago
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