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Papessa [141]
3 years ago
6

Given the following table, what is the y-intercept of this linear function?

Mathematics
2 answers:
hammer [34]3 years ago
6 0
Adding three every time answer is 3
asambeis [7]3 years ago
6 0

Answer:

3 is the correct answer.

Step-by-step explanation:

3 is being added to y at a constant rate. The coordinates would be (1, 3)

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What were the major changes introduced in industry by Stalin explain <br>​
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3 years ago
CONSTRUCTED-RESPONSE ITEM 14. Four people each deliver food to people's homes.
rodikova [14]

Answer:

I'm Pretty Sure it is $16.20

Step-by-step explanation:

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3 0
3 years ago
the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev
Naya [18.7K]

Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 16, \sigma = 2.1

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 16}{2.1}

Z = 1.905

Z = 1.905 has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

Out of 180

0.0284*180 = 5.112 days

4 0
3 years ago
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