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almond37 [142]
2 years ago
9

Does the wireless signal between the cell phones require matter to travel from one phone to another?

Computers and Technology
1 answer:
mrs_skeptik [129]2 years ago
3 0

Mobile phones transmit and receive signals using electromagnetic waves, that is, wireless signal are electromagnetic waves which can travel through a vacuum, they do not need a medium or matter.

<h3>What are electromagnetic waves?</h3>

They are generated by electrical and magnetic particles moving at the same time (oscillating).

<h3>Characteristics of electromagnetic waves</h3>

  • Network waves are electromagnetic waves.

  • A mobile phone has coverage when it receives electromagnetic waves from at least one base station.

  • They do not necessarily require a material medium for their propagation.

Therefore, we can conclude that electromagnetic waves are those that do not need a material medium to propagate and include, among others, radio, television and telephone waves.

Learn more about electromagnetic waves here: brainly.com/question/13803241

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I believe you will find all your answers here,

http://www.csun.edu/prospectivestudents/cost-attendance
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4 years ago
Can I ask a question about information technology (IT)...
lianna [129]

Answer:

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3 0
3 years ago
Your teacher want to store 12 videos she wants to store on the school network .The average size of each file is 4.8 gigabytes .H
torisob [31]

Answer: About 57.6GBS

Explanation:

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8 0
2 years ago
Write a method named printOdd() that accepts an integer array as argument and print all the odd numbers in the array. You may as
Hoochie [10]

Answer & Explanation:

//written in java

public class Main {

   private static void printOdd(int[] list) {

       for (int value : list) {

           if (value % 2 == 1) {

               System.out.println(value);

           }

       }

   }

   public static void main(String[] args) {

       printOdd(new int[]{5, 6, 2, 3, 11, 4, 7});

   }

}

8 0
4 years ago
Write a C++ program that searches for anagrams in a dictionary. An anagram is a word obtained by scrambling the letters of some
Semmy [17]

Answer:

d, avt, car, feet, more, pitch, rome, tac, teef,

Anagrams of b in dictionary

Anagrams of cat in dictionary

avt, cat, tac,

Anagrams of room in dictionary

more, rome,

Anagrams of hello in dictionary

Anagrams of  in dictionary

Explanation:

// FindAnagrams.cpp : it is the starting point of application console.

//

#include <vector>

#include <hash_map>

#include <iostream>

#include <string>

#include <algorithm>

#include <map>

#include <set>

using namespace std;

using namespace stdext;

bool IsAnagrams(string& strA, string& strB)

{

   list<char> listA(strA.begin(), strA.end());

   list<char> listB(strB.begin(), strB.end());

   listA.sort();

   listB.sort();

   return listA == listB;

   // return equal(listA.begin(), listA.end(), listB.begin());

}

string SortChars(string str)

{

   list<char> l(str.begin(), str.end());

   l.sort();

   return string(l.begin(), l.end());

}

set<string> FindAnagrams(list<string>& dict, string findStr)

{

   map<string, set<string>> d;

   typedef pair<string, set<string>> MyPair;

   for(list<string>::const_iterator it = dict.begin(); it != dict.end(); ++it){

       string str(SortChars(*it));

       if(d.find(str) == d.end()){

           set<string> s;

           s.insert(*it);

           d.insert(MyPair(str, s));

       }

       else{

           d[str].insert(*it);

       }

   }

   string sortedStr(SortChars(findStr));

   return d[sortedStr];

}

int main(int argc, char* argv[])

{

   list<string> dict;

   dict.push_back("c");

   dict.push_back("car");

   dict.push_back("avt");

   dict.push_back("taac");

   dict.push_back("feet");

   dict.push_back("teef");

   dict.push_back("rom");

   dict.push_back("more");

   dict.push_back("pit");

   dict.sort();

   cout << "The dictionary: " << endl;

   copy(dict.begin(), dict.end(), ostream_iterator<string>(cout, ", "));

   cout << endl;

   list<string> testCases;

   testCases.push_back("d");

   testCases.push_back("car");

   testCases.push_back("rome");

   testCases.push_back("hell");

   testCases.push_back("");

   for(list<string>::iterator it = testCases.begin(); it != testCases.end(); ++it)

   {

       cout << endl << "Anagrams of " << *it << " in dictionary" << endl;

       set<string> output = FindAnagrams(dict, *it);

       copy(output.begin(), output.end(), ostream_iterator<string>(cout, ", "));

       cout << endl;

   }

   return 0;

}

8 0
3 years ago
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