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2 years ago

What happened to the proton after absorbing an electron?

Chemistry

1 answer:

Vlad [161]2 years ago

5 0

Answer:

What happened to the proton after absorbing an electron? It becomes neutral.

Explanation:

hope this helps

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How do you name ionic compounds?

ryzh [129]

Answer:

Consult the periodic table of elements

Explanation:

When naming ionic compounds, all of the information you’ll need is on the periodic table. Ionic compounds are formed of a metal (cation) and a non-metal (anion). You can find metals on the left and central sections of the periodic table (e.g., Barium, Radium, and Lead), while you can find non-metals on the right side of the table.[1]

6 0

3 years ago

Many hospitals, and some doctors\' offices, use radioisotopes for diagnosis and treatment, or in palliative care (relief of symp

jekas [21]

Answer:

For a: The isotopic symbol of the above atom will be $_{53}^{131}\textrm{I}$

For b: The isotopic symbol of the above atom will be $_{77}^{192}\textrm{Ir}$

For c: the isotopic symbol of the above atom will be $_{62}^{153}\textrm{Sm}$

Explanation:

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

For a: Iodine-131

Atomic number of iodine = 53

Mass number of iodine = 131

Symbol of iodine = I

The isotopic symbol of the above atom will be $_{53}^{131}\textrm{I}$

For b: Iridium-192

Atomic number of iridium = 77

Mass number of iridium = 192

Symbol of iridium = Ir

The isotopic symbol of the above atom will be $_{77}^{192}\textrm{Ir}$

For c: Samarium-153

Atomic number of samarium = 62

Mass number of samarium = 153

Symbol of samarium = Sm

The isotopic symbol of the above atom will be $_{62}^{153}\textrm{Sm}$

7 0

3 years ago

Determine if the following two structures are

kherson [118]

Answer:

Constitutional isomers vs stereoisomers

Structural (constitutional) isomers have the same molecular formula but a different bonding arrangement among the atoms. Stereoisomers have identical molecular formulas and arrangements of atoms. They differ from each other only in the spatial orientation of groups in the molecule.

Explanation:

4 0

3 years ago

Please hurry! And help!!

lyudmila [28]

Answer:

I guess the answer is compound

Explanation:

Coz compound it is on there playing with me again Go ahead and paste it in the class

4 0

3 years ago

The element boron exists in nature as two isotopes: 10B has a mass of 10.0129 u, and 11B has a mass of 11.0093 u. The average at

Shalnov [3]

Answer:

Percentage abundance of B 10 is = 20 %

Percentage abundance of B 11 is = 80 %

Explanation:

The formula for the calculation of the average atomic mass is:

$Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})$

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, B 10:

% = x %

Mass = 10.0129 u

For second isotope, B 11:

% = 100 - x

Mass = 11.0093 u

Given, Average Mass = 10.81 u

Thus,

$10.81=\frac{x}{100}\times {10.0129}+\frac{100-x}{100}\times {11.0093}$

$10.0129x+11.0093\left(100-x\right)=1081$

Solving for x, we get that:

x = 20 %

Thus percentage abundance of B 10 is = 20 %

Percentage abundance of B 11 is = 100 - 20 % = 80 %

8 0

3 years ago

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