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3 years ago

An acid has a molarity of 0.01 M. What does the 0.01 M refer to?

2 answers:

3 0

So molarity which is represented by that 0.01M refers to the amount of moles that is present in 1L or 1dm³ of the substance, in this case the acid. Molarity refers to CONCENTRATION therefore and has little to do with the strength of the acid (the strength is dependent on the pH).

Thus your answer is OPTION B

marta [7]3 years ago

3 0

Answer : The correct option is, the concentration of the acid.

Explanation :

Molarity : It is defined as the number of moles of solute present in one liter of solution. It is represented by symbol, M. The molarity is also know as concentration.

The unit of molarity or concentration is, moles per liter or, mole/L

As we are given that, the acid has a molarity of 0.01 M that means the 0.01 M refers to the concentration of the acid or, 0.01 mole of acid present in 1 liter of solution.

Hence, the correct option is, the concentration of the acid.

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$T_{initial} = -55.0^0C$
converting to Kelvin
TK = TC + 273
TK = -55.0 + 273 → TK = 218.0 → $T_{initial} = 218.0\:K$
$V_{final} = ? (in\:milliliters)$
$T_{final} = 30.0^0C$
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By the first Law of Charles and Gay-Lussac, we have:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$

Solving:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$
$\frac{ 590 }{ 218.0 } = \frac{ V_{f} }{ 303.0 }$
Product of extremes equals product of means:
$218.0* V_{f} = 590*303.0$
$218.0 V_{f} = 178770$
$V_{f} = \frac{178770}{218.0}$
$\boxed{\boxed{V_{f} \approx 820.04\:mL}}\end{array}}\qquad\quad\checkmark$

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