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777dan777 [17]
4 years ago
14

Please help me due today at 7:00pm please help giving more points please help me

Chemistry
1 answer:
kkurt [141]4 years ago
6 0
The answer is 20N as when the object is accelerating at 3 m/s2 it as a force of 10N applied to it so to get to 6m/s2 3(x2) = 6 so 10(x2) = 20
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The reduced vapor pressure at high altitudes causes a liquid to boil at a temperature.
irinina [24]
<span>At higher altitudes (and thus lower atmospheric pressures), water boils at a lower temperature. This is because the lack of vapor pressure at that altitude doesn't constrain the speed of the molecules with barometric pressure. Therefore, the water begins boiling at a lower temperature. This is often a disadvantage because even if the water is boiling, it won't be hot enough for meals (which is why heat and temperature are distinct). That's why we have pressure cookers, which manage to keep a stable boiling point.
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5 0
3 years ago
Read 2 more answers
[06.01]The same amount of heat is removed from 2 kg of water and from 1 kg of water starting at the same temperature. What will
liq [111]
<span>Answer: The 1 kg of water will reach the lowest temperature
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Both of the objects is water so their specific heat should be same. The heat removed from the 2kg of water which is 2 times of mass than the 1kg water. Since the heat removed, both of their temperatures will drops. But 2kg water temperature drops will be half of 1kg water.
6 0
3 years ago
Write the ions that result from the dissociation of na2s
Sveta_85 [38]
2Na^+ and S^2-

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5 0
4 years ago
List 3 ways to increase the solubility of a liquid
Semenov [28]

Answer:

Three ways I can come up with are increasing the temperature, increased the amount of solvent, and using a solvent with similar polarity as the solute.

Explanation:

5 0
3 years ago
Boyle's Law expresses the pressure-volume
Colt1911 [192]

Answer:

\large \boxed{\text{175. atm}}

Explanation:

Data:

p₁ = 1.00 atm; V₁ = 350.      L

p₂ = ?;             V₂ =     2.00 L

Calculation:

\begin{array}{rcl}p_{1}V_{1} & = & p_{2}V_{2}\\\text{1.00 atm} \times \text{350. L} & = & p_{2} \times\text{2.00 L}\\\text{350. atm} & = & 2.00p_{2}\\p_{2} & = & \dfrac{\text{350. atm}}{2.00}\\\\& = &\textbf{175. atm}\\\end{array}\\\text{It would take a pressure of $\large \boxed{\textbf{175. atm}}$ to compress the gas.}

8 0
3 years ago
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