Answer:
= 3.78 g H₂O
Explanation:
2C₂H₆ + 3O₂ => 4CO₂ + 6H₂O
2.1g C₂H₆ = 2.1g/30.0 g/mol = 0.07 mole ethane
3.68g O₂ = 3.68g/32 g/mol = 0.115 mole oxygen
Limiting Reactant:
A quick way to determine limiting reactant is to divide moles of reactant by its respective coefficient in the balanced molecular equation. The smaller value is the limiting reactant.
moles ethane = 0.07 mole / 2 (the coefficient in balanced equation) = 0.035
moles oxygen = 0.115 mole / 3 (the coefficient in balanced equation) = 0.038
Since the smaller value is associated with ethane, then ethane is the limiting reactant and the problem is worked from the 0.07 moles of ethane in an excess of O₂.
From the equation stoichiometry ...
2 moles C₂H₆ in an excess of O₂ => 6 moles H₂O
then 0.07 mole C₂H₆ in an excess of O₂ => 6/2(0.07 moles H₂O = 0.21 mole
Converting to grams of water produced
= 0.21 mole H₂O X 18 g/mol = 3.78 g H₂O
Explanation:
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Answer:
The particles of matter are in constant motion.
Explanation:
Let us consider each statement:
1) Matter consists of only large molecules: No it is not necessary that matter consists of only large molecules, it depends upon the nature of matter.
2) Matter is made up of only charged particles: no the matter may have any kind of particles charged or uncharged.
3) The particles of matter are in constant motion: Yes according to kinetic theory the matter particles are in constant motion.
4)The particles of matter have zero kinetic energy: it is not possible.
Answer:
A is Carbon atom ; B is Nitrogen C is Nitrogen D is oxygen
Explanation:
A is is isotope of Carbon atom with proton 6 electrons and 8 neutrons, B is Nitrogen atom with 7 protons and 7 neutrons, C is Isotope of Nitogen with 7 protons and 8 neutrons and D is isotope of oxygen with 8 protons and 7 neutrons.
