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Kitty [74]
2 years ago
8

Clinical trials involved treating flu symptoms with a new medicine. Among 724 patients treated

Mathematics
1 answer:
schepotkina [342]2 years ago
8 0

According to the null hypothesis, the test statistic of the proportion is of z = 120.1.

<h3>What is the null hypothesis?</h3>

The claim is that the rate of nausea is greater than the 6% rate experienced by flu patients given a placebo. At the null hypothesis, we consider the claim as false, hence the null hypothesis is:

H_0: p \leq 0.06

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

In this problem, the parameters are:

p = 0.06, n = 724, \overline{p} = \frac{72}{724} = 0.0994

Hence, the test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

z = \frac{0.0994 - 0.06}{\sqrt{\frac{0.06(0.94)}{724}}}

z = 120.1

You can learn more about test statistic at brainly.com/question/16313918

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Answer:

my answer is 19.90

Step-by-step explanation: so what i did to get this answer is by adding all the numbers so i stack it in order of greater number to least numbers so i did 19.76 + $8 + 6 ( you don't have to put the dollar sign when you add the numbers) and after i added those i got 19.90 as my answer.

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5 0
4 years ago
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The random variable K has a geometric distribution with mean 16. Which of the following is closest to the standard deviation of
sdas [7]

Answer: d. 15.49

Step-by-step explanation:

Given : The random variable K has a geometric distribution with mean 16.

Formula for Mean and standard deviation in geometric distribution:

\mu=\dfrac{1}{p}    (1)

\sigma=\dfrac{\sqrt{1-p}}{p}   (2), where p is the probability of success in each trial.

Since \mu=16  (Given)

Then from (1) ,

\dfrac{1}{p}=16\\\Rightarrow\ p=\dfrac{1}{16}=0.0625

Put value of p in (2),

\sigma=\dfrac{\sqrt{1-0.0625}}{0.0625}=\dfrac{\sqrt{0.9375}}{0.0625}  

=\dfrac{0.968245836552}{0.0625}

=15.4919333848\approx15.49

Hence, the standard deviation of random variable K is closest to 15.49.

Therefore , the correct answer is d. 15.49 .

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Val walks 2 3/5 miles each day. Bill runs 10 miles once every 4 days. In 4 days, who covers the greater distance?
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Val does because he covers 10.4 miles. Hope that helps.
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4 years ago
Y+2=-3(x+2) answer fast please i need it now <br> \
Zepler [3.9K]

Answer:

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3 years ago
A class consists of 23 women and 83 mean. If a student is random selected, what is the probability that the student is a woman?
slavikrds [6]

Answer:

P(Woman) = \frac{23}{106}

Step-by-step explanation:

Given

Women = 23

Men = 83

Required

P(Woman)

This is calculated as the number of women divided by the population of the class

i.e.

P(Woman) = \frac{Women}{Women + Men}

So, we have:

P(Woman) = \frac{23}{23+83}

P(Woman) = \frac{23}{106}

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3 years ago
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