hello : <span>
<span>the discriminat of each quadratic equation :
ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 ) Δ > 0 the equation has two reals solutions : x1,2 =
(-b±√Δ)/2a</span></span>
factoring :
<span>ax²+bx+c = a(x-x1)(x-x2)
2 ) Δ = 0 : one solution : x1 = x2 = -b/2a</span>
factoring :
<span>ax²+bx+c = a(x-x1)²
3 ) Δ < 0 : no reals solutions... no </span>
<span>factoring </span>
Answer:
b=1
Step-by-step explanation:
-11+3(b+5)=7
-11+3b+15=7
-11+15+3b=7
4+3b=7
3b=7-4
3b=3
3b/3=3/3
b=1
hope it's helpful
Answer:
What do you mean DUO?
Step-by-step explanation:
In this problem, we can imagine that all the points
connect to form a triangle. The three point or vertices are located on the
pitcher mount, the home plate and where the outfielder catches the ball. So in
this case we are given two sides of the triangle and the angle in between the
two sides.
<span>With the following conditions, we can use the cosine law
to solve for the unknown 3rd side. The formula is:</span>
c^2 = a^2 + b^2 – 2 a b cos θ
Where,
a = 60.5 ft
b = 195 ft
θ = 32°
Substituting the given values:
c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32
c^2 = 3660.25 + 38025 – 20009.7
c^2 = 21,675.56
c = 147.23 ft
<span>Therefore the outfielder throws the ball at a distance of
147.23 ft towards the home plate.</span>
Answer:
D. None of the above; the triangles cannot be proven similar
Step-by-step explanation:
There are no signs that shows the triangles are similar or congruent for given information. So the answer is last option :
D. None of the above; the triangles cannot be proven similar
