V₁(O2) = 6.50<span> L
</span>p₁(O2) = 155 atm
V₂(acetylene) = <span>4.50 L
</span>p₂(acetylene) =?
According to Boyle–Mariotte law (At constant temperature and unchanged amount of gas, the product of pressure and volume is constant) we can compare two gases that have ideal behavior and the law can be usefully expressed as:
V₁/p₁ = V₂/p₂
6.5/155 = 4.5/p₂
0.042 x p₂ = 4.5
p₂ = 107.3 atm
Answer:
2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂
2Na + MgCl₂ → 2NaCl + Mg
Explanation:
A balanced chemical equation is a chemical equation that have an equal number of elements of each type on both sides of the equation
Among the given chemical reactions, we have;
2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂
In the above reaction;
The number of phosphorus, P, on either side of the equation = 2
The number of bromine atoms, Br, on either side of the equation = 6
The number of chlorine atoms, Cl, on either side of the equation = 6
Therefore, the number of elements in the reactant side and products side of the reaction are equal and the reaction is balanced
The second balanced chemical reaction is 2Na + MgCl₂ → 2NaCl + Mg
In the above reaction, there are two sodium atoms, Na, one magnesium atom and two chlorine atoms on both sides of the reaction, therefore, the reaction is balanced
Answer:
C
Explanation:
The pattern is adding .5 to the cm every .1 in weight you just continue the table
Answer:
Wnet, in, = 133.33J
Explanation:
Given that
Pump heat QH = 1000J
Warm temperature TH= 300K
Cold temperature TL= 260K
Since the heat pump is completely reversible, the combination of coefficient of performance expression is given as,
From first law of thermodynamics,
COP(HP, rev) = 1/(1-TL/TH)
COP(HP, rev) = 1/(1-260/300)
COP(HP, rev) = 1/(1-0.867)
COP(HP, rev) = 1/0.133
COP(HP, rev) = 7.5
The power required to drive the the heat pump is given as
Wnet, in= QH/COP(HP, rev)
Wnet, in = 1000/7.5
Wnet, in = 133.333J. QED
So the 133.33J was the amount heat that was originally work consumed in the transfer.
Extra....
According to the first law, the rate at which heat is removed from the low temperature reservoir is given as
QL=QH-Wnet, in
QL=1000-133.333
QL=866.67J
