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NISA [10]
2 years ago
13

What is the average speed of a cheetah that runs 88 m in 5 seconds

Physics
1 answer:
vovangra [49]2 years ago
5 0

So, the average speed of the Cheetah is 17.6 m/s.

<h3>Introduction</h3>

Hello ! I'm Deva from Brainly Indonesia. This time, I will help regarding the average speed. The average speed is obtained from finding the average of the speeds that occur or can be detected from the division between distance and travel time. The average speed can be formulated by :

\boxed{\sf{\bold{\overline{v} = \frac{s}{t}}}}

With the following condition :

  • \sf{\overline{v}} = average speed (m/s)
  • s = shift or distance objects from initial movement (m)
  • t = interval of the time (s)

<h3>Problem Solving</h3>

We know that :

  • s = shift = 88 m
  • t = interval of the time = 5 seconds

What was asked :

  • \sf{\overline{v}} = average speed = ... m/s

Step by step :

\sf{\overline{v} = \frac{s}{t}}

\sf{\overline{v} = \frac{88}{5}}

\boxed{\sf{\overline{v} = 17.6 \: m/s}}

So, the average speed of the Cheetah is 17.6 m/s.

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How to find velocity
Valentin [98]
V=d/t 

v=speed 
d=distance traveled
t=time taken

hope this helps 
8 0
3 years ago
A stone with a weight of 5.29 N is launched vertically from ground level with an initial speed of 26.0 m/s, and the air drag on
makkiz [27]

Answer:

a) 19.4 m/s

b) 19 m/s

Explanation:

a) In the given question,

the potential energy at the initial point = Ui = 0

the potential energy at the final point = Uf = mgh

the kinetic energy at the initial point = Ki = 1/2 mv₀².

the kinetic energy at the final point = Kf = 0

work done by air= Ea= fh =  0.262 N

Now, using the law of conservation of energy

initial energy= final energy

Ki +Ui = Kf + Uf +Ea

1/2 mv₀² + 0 = 0 + mgh + fh

1/2 mv₀² = mgh + fh

h = v₀²/ 2g (1 +f/w)

calculate m

m= w/g = 5.29 /9.8

= 0.54 kg

h = 20 ²/ (2 x9.80) x (1 0.265/5.29)

h = 19.4 m.

b) 1/2 mv² + 2fh = 1/2 mv₀²

Vg = 19 m/s

6 0
2 years ago
The membrane that surrounds a certain type of living cell has a surface area of 5.3 x 10-9 m2 and a thickness of 1.1 x 10-8 m. A
kotykmax [81]

Answer:

2.1\times 10^{-12} c

Explanation:

We are given that

Surface area of membrane=5.3\times 10^{-9} m^2

Thickness of membrane=1.1\times 10^{-8} m

Assume that membrane behave like a parallel plate capacitor.

Dielectric constant=5.9

Potential difference between surfaces=85.9 mV

We have to find the charge resides on the outer surface of membrane.

Capacitance between parallel plate capacitor is given by

C=\frac{k\epsilon_0 A}{d}

Substitute the values then we get

Capacitance between parallel plate capacitor=\frac{5.9\times 8.85\times 10^{-12}\times 5.3\times 10^{-9}}{1.1\times 10^{-8}}

C=0.25\times 10^{-12}F

V=85.9 mV=85.9\times 10^{-3}

Q=CV

Q=0.25\times 10^{-12}\times 85.9\times 10^{3}=2.1\times 10^{-12} c

Hence, the charge resides on the outer surface=2.1\times 10^{-12} c

5 0
3 years ago
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If your mass is 20kg, and you stand on the scale (witch is your force), and the acceleration due to gravity is10m/s^2, what does
Phantasy [73]
Weight = (mass) x (gravity)

= 200 Newtons.

(About 44 pounds. You're very skinny.)
5 0
3 years ago
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A perpetual-motion machine can never be built because it is not possible to eliminate...
bazaltina [42]
The answer is:  [C]:  "elasticity" .
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