<h3>
Answer: 12</h3>
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Explanation:
You can use the AAS (angle angle side) theorem to prove that triangle ABD is congruent to triangle CBD.
From there, we can then say that AD and DC are the same length
AD = DC
3y+6 = 5y-18
3y-5y = -18-6
-2y = -24
y = (-24)/(-2)
y = 12
Answer:
Dilation factor = 0.75.
Step-by-step explanation:
One point on the xy-plane is (-24,-12). The transformation is the dilation which is done on the point and the image is given by (-18,-9). Dilation changes the size of the shape according to the dilation factor. If the original x-coordinate is -24, then the image will be calculated by multiplying the original point with the dilation factor. Therefore, -18= -24 * k, where k is the unknown dilation factor. Simply solve the equation for k.
24k = 18.
k = 18/24 = 3/4 = 0.75.
Similarly, 12k = 9. k = 9/12 = 3/4 = 0.75.
So the point (-24,-12) dilated by k=0.75 to get to (-18,-9)!!!
when dividing subtract the powers
so you would do 6-2 = 4
so b = 4
Answer:
option A is correct answer
divide both sides with 2
hope it helps
Hi there what you need is lagrange multipliers for constrained minimisation. It works like this,
V(X)=α2σ2X¯1+β2\sigma2X¯2
Now we want to minimise this subject to α+β=1 or α−β−1=0.
We proceed by writing a function of alpha and beta (the paramters you want to change to minimse the variance of X, but we also introduce another parameter that multiplies the sum to zero constraint. Thus we want to minimise
f(α,β,λ)=α2σ2X¯1+β2σ2X¯2+λ(\alpha−β−1).
We partially differentiate this function w.r.t each parameter and set each partial derivative equal to zero. This gives;
∂f∂α=2ασ2X¯1+λ=0
∂f∂β=2βσ2X¯2+λ=0
∂f∂λ=α+β−1=0
Setting the first two partial derivatives equal we get
α=βσ2X¯2σ2X¯1
Substituting 1−α into this expression for beta and re-arranging for alpha gives the result for alpha. Repeating the same steps but isolating beta gives the beta result.
Lagrange multipliers and constrained minimisation crop up often in stats problems. I hope this helps!And gosh that was a lot to type!xd
